Answer:
Find a polynomial function whose graph passes through (6,13), (9,-11), (0,5)
1 Answers
Assuming a quadratic, we have that
y = ax^2 + bx + c
Since (0,5) is on the graph, c =5
And we have the remaining system
a(9)^2 + b(9) + 5 = -11
a(6)^2 + b(6) + 5 = 13 simplify
81a + 9b = -16 multiply through by 6 ⇒ 486a + 54b = - 96 (1)
36a + 6b = 8 multiply through by -9 ⇒ -324a -54b = -72 (2)
Add (1) and (2)
162a = -168
a = -28/27
To find b we have
36 (-28/27) + 6b = 8
-112/3 + 6b = 8
⇒ b = 68/9
The function is
y = - (28/27)x^2 + (68/9)x + 5
Answer:
a and b maybe
Step-by-step explanation:
Step-by-step explanation:
75 . 727 is your answer
hope it is helpful to you
Answer:
15v^5+4v^3-24v^2
Step-by-step explanation:
Distribute the Negative Sign:
=3v5+8v3−10v2+−1(−12v5+4v3+14v2)
=3v5+8v3+−10v2+−1(−12v5)+−1(4v3)+−1(14v2)
=3v5+8v3+−10v2+12v5+−4v3+−14v2
Combine Like Terms:
=3v5+8v3+−10v2+12v5+−4v3+−14v2
=(3v5+12v5)+(8v3+−4v3)+(−10v2+−14v2)
=15v5+4v3+−24v2
Answer:
=15v5+4v3−24v2
Hope this helps! :)