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Dimas [21]
3 years ago
14

Mary logged into work at 8:10 am and logged out at 3:45 pm. How many hours did she work? (Her employer rounds to the nearest qua

rter hour.)
Mathematics
2 answers:
Leno4ka [110]3 years ago
5 0

Answer:

Mary worked 7 and a half hours.

Step-by-step explanation:

The easiest way to solve this is converting to the 24 hours metric.

In this metric, 8:10 am is 8h, 10 min.

3:45 pm is 12+3 = 15h, 45 min.

Rounded to the nearest quarter hour, Mary worked 15-8 = 7h, 45-10 = 35 min, Mary worked 7 and a half hours.

IRINA_888 [86]3 years ago
3 0
First we count how many hours is inbetween 8 and 3  which is 7

then subtract 10 for the first time

6:50 then add 45 for the second time

7:35

round down so she worked 7 1/2 hours
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What is 75 minutes to ten hours in ratio and simplest form
Arada [10]

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1:8

Step-by-step explanation:

75min/10hr

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7 0
3 years ago
Approximate the value of 5 π
olya-2409 [2.1K]

Answer with explanation:

→π is an Irrational Number.

→Decimal Representation of π is non terminating non repeating.

\pi=\frac{\text{Circumference of Circle}}{\text{Diameter}}\\\\\pi =3.14\\\\ 5\pi =5 \times 3.14=15.70

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8 0
3 years ago
Read 2 more answers
HELP I DON'T UNDERSTAND THIS AT ALL!!!
Hatshy [7]

D__ is 7.5<x

C is x<10

Step-by-step explanation:

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7 0
3 years ago
A batch of 40 semiconductor chips is inspected by choosing a sample of 5 chips. Assume 10 of the chips do not conform to custome
butalik [34]

Answer:

a) 658008 samples

b) 274050 samples

c) 515502 samples

Step-by-step explanation:

a) How many ways sample of 5 each can be selected from 40 is just a combination problem since the order of selection isn't important.

So, the number of samples = ⁴⁰C₅ = 658008 samples

b) How many samples of 5 contain exactly one nonconforming chip?

There are 10 nonconforming chips in the batch, and 1 nonconforming chip for the sample of 5 be picked from ten in the following number of ways

¹⁰C₁ = 10 ways

then the remaining 4 conforming chips in a sample of 5 can be picked from the remaining 30 total conforming chips in the following number of ways

³⁰C₄ = 27405 ways

So, total number of samples containing exactly 1 nonconforming chip in a sample of 5 = 10 × 27405 = 274050 samples

c) How many samples of 5 contain at least one nonconforming chip?

The number of samples of 5 that contain at least one nonconforming chip = (Total number of samples) - (Number of samples with no nonconforming chip in them)

Number of samples with no nonconforming chip in them = ³⁰C₅ = 142506 samples

Total number of samples = 658008

The number of samples of 5 that contain at least one nonconforming chip = 658008 - 142506 = 515502 samples

6 0
3 years ago
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