<u>Answer
</u>
4
<u>Explanation
</u>
AP is a tangent meeting a secant BP at P outside the circle.
(PA)² = (PE)(PB)
PA = 6 and chord BE= 5.
Let PE = x
6² = x(x+5)
36 = x² + 5x
x² + 5x + 2.5² = 36 + 2.5²
(x + 2.5)² = 42.25
(x + 2.5) = √ 42.25 = 6.5
x = 6.5 - 2.5 = 4 or x = -6.5 - 2.5 = -9
But since length cannot be negative, x = 4.
Answer:
Step-by-step explanation:add 4 to the side that has "13" then you will get "17" then divided -7 from x and "17"and your answer is x=idk
<span>2x + y = 5
6x + 3y = 25
Multiply both sides of the first equation by 3.
6x + 3y = 15
Now subtract it from the second equation.
0 = 10
Since 0 = 10 is a false statement, there is no solution.
Answer: b. inconsistent, none
</span>
Answer:
12a - 18
Step-by-step explanation:
6 x 2 = 12 (then add the "a" = 12a
6 x 3 = 18
put the minus in the middle then get
12a- 18
Answer:
My day is going good so far
Anyways, the answer is 7 21/25
Step-by-step explanation:
4 + 8/5 + 8/5 + 16/25 =
4 + 16/5 + 16/25 =
4 + 80/25 + 16/25 =
4 + 96/25 =
4 + 3 + 21/25 =
7 + 21/25 =
7 21/25