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3 years ago

7x15÷3-2 put one set of brackets

Mathematics

2 answers:

Molodets [167]3 years ago

7 0

7(15\3-2) because GEMDAS OR PEMDAS

Lapatulllka [165]3 years ago

7 0

You would do 7x(15 divided by 3-2)

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Classify each polynomial and determine its degree. the polynomial 3x2 is a with a degree of . the polynomial x2y 3xy2 1 is a wit

Fofino [41]

$\rm 3x^2$ is the polynomial of one variable with second-order and $x^2y+3xy^2+1$ is the polynomial of two variables with third-order

<h3>What is polynomial?</h3>

Polynomial is the combination of variables and constants in a systematic manner with "n" number of power in ascending or descending order.

We have polynomials:

$\rm 3x^2$ and

$x^2y+3xy^2+1$

For $3x^2$

In this polynomial, the number of variables is one and the maximum power of x is 2, therefore:

This is the polynomial of one variable with second order.

In polynomial, $x^2y+3xy^2+1$ there are two variables x and y.

The maximum power of x is 3( x has a power of 2 and y has a power of 1)

This is the polynomial of two variables with third order.

Thus, $\rm 3x^2$ is the polynomial of one variable with second-order and $x^2y+3xy^2+1$ is the polynomial of two variables with third-order.

Learn more about Polynomial here:

brainly.com/question/17822016

7 0

2 years ago

Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits

scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

$x^{2} + 3x - 8^{- 14} = 0$

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

The above solution is for the quadratic equation of the form:

$ax^{2} + bx + c = 0$

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

From the given eqn

a = 1

b = 3

c = $- 8^{- 14}$

Now, using the above values in the formula mentioned above:

$x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)$

Now, Rationalizing the above eqn:

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

$x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

Solving the above eqn:

$x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}$

Solving with the help of caculator:

$x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}$

The precise value upto three decimal places comes out to be:

$x_{1, 1'} = 0.758\times 10^{- 14}$

5 0

3 years ago

One crew can seal a parking lot in 12 hours and another in 15 hours. how long will it take to seal the parking lot if the two cr

MakcuM [25]

This is a typical work problem in algebra. The approach to this is using the equation: Rt = 1, where R is the rate per person working, t is the amount of time worked by an individual. All their rates must equal to 1. The solution is as follows:

12/x + 15/x = 1
Solving for x,
x = 27 hours

So, if they work together, they can finish the work in 27 hours.

6 0

3 years ago

A man lives next to a circular park it takes him to 80 minutes to walk around it in a clockwise direction but one hour and 20 mi

Zigmanuir [339]

Its the same time 80 minutes= 1 hour and 20 minutes

8 0

1 year ago

Solve for N <br> A 24<br> B 54<br> C 42<br> D 94.5

Nookie1986 [14]

Answer:

54 0r 42 I think

Step-by-step explanation: