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myrzilka [38]
3 years ago
15

Writing a Verbal Expression for an Algebraic Expression

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0

Answer:

three times x to the power of four

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The length of a 1-inch paperclip is about 1.6 x 10−5 miles. It takes about 1.5 x 1010 paperclips linked together to reach the mo
son4ous [18]

Answer:

Distance from the moon is 2.4 × 10⁵ miles

Step-by-step explanation:

Length of 1-inch paperclip = 1.6\times 10^{-5} miles

Number of paperclips used to reach the moon = 1.5 × 10¹⁰

Total distance from the moon = Number of paper clips used × Length of one clip

= (1.5 × 10¹⁰) × (1.6 × 10⁻5)

= (1.5 × 1.6) (10¹⁰× 10⁻⁵)

= 2.4 × 10⁽¹⁰⁻⁵⁾ miles

= 2.4 × 10⁵ miles

Distance from the moon is 2.4 × 10⁵ miles.

5 0
3 years ago
Advance Algebra Logarithm Task
valina [46]

9514 1404 393

Answer:

  3.65% monthly

Step-by-step explanation:

The same amount is invested for the same period in all accounts, so we only need to determine the effective annual rate in order to compare the accounts.

For compounding annual rate r n times per year, the effective annual rate is ...

  (1 +r/n)^n -1

For the same rate r, larger values of n cause effective rate to be higher. As a consequence, we know that 3.65% compounded quarterly will not have as great a yield as 3.65% compounded monthly. The effective rate for the monthly compounding is ...

  (1 +0.0365/12)^12 -1 = 3.712%

The effective rate for continuous compounding is ...

  e^r -1

For a continuously compounded rate of 3.6%, the effective annual rate is ...

  e^0.036 -1 = 3.666%

This tells us the best yield is in the account bearing 3.65% compounded monthly.

_____

If i is the effective annual rate of interest as computed by the methods above, then the 10-year account balance will be ...

  10000×(1 +i)^10

This is the formula used in the spreadsheet to calculate the balances shown.

4 0
3 years ago
The graph below shows the solution to an inequality
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Answer:cheese monkuey㏒㏑to amogus

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baby monkey

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3 years ago
What requirements are necessary for a normal probability distribution to be a standard normal probability​ distribution?Choose t
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Answer:

B.The mean and standard deviation have the values of mu equals 0and sigma equals 1

Step-by-step explanation:

The mean and standard deviation have the values of µ = 0 and σ = 1.

This is the requirement for any normal distribution curve to fulfil in order to be  a standard normal probability​ distribution.

3 0
3 years ago
Which of the following inequalities defines the graph below ( Uppercase = _ under >)
timurjin [86]

Answer:

A. x\geq -3

Step-by-step explanation:

See attached file :)

Hope this helps

All the love, Ya boi Fraser

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