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Tcecarenko [31]
2 years ago
5

(5-(-4)^2)^2)

Mathematics
1 answer:
stepladder [879]2 years ago
6 0

Answer:

121

Step-by-step explanation:

You are missing a parentheses

Assuming you just mean to close the parentheses

((5-(-4)^2)^2)

The first step is to complete the inside parentheses

PEMDAS

(5-(-4)^2)

Do the exponents first

(5-(16))

-11

Put this in the equation for (5-(-4)^2)

(-11) ^2

121

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Step-by-step explanation

Given,

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According To the Question,

  • a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

  • b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

        thus , ∠ABC=76° .

  • c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

   

  • d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre  

For Diagram, Please Find in Attachment  

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