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1 year ago

(5-(-4)^2)^2)

Mathematics

1 answer:

stepladder [879]1 year ago

6 0

Answer:

121

Step-by-step explanation:

You are missing a parentheses

Assuming you just mean to close the parentheses

((5-(-4)^2)^2)

The first step is to complete the inside parentheses

PEMDAS

(5-(-4)^2)

Do the exponents first

(5-(16))

-11

Put this in the equation for (5-(-4)^2)

(-11) ^2

121

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Answer:

E. 0.11

Step-by-step explanation:

We have these following probabilities:

A 10% probability that a person has the flu.

A 90% probability that a person does not have the flu, just a cold.

If a person has the flu, a 99% probability of having a runny nose.

If a person just has a cold, a 90% probability of having a runny nose.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem, we have that:

What is the probability that a person has the flu, given that she has a runny nose?

P(B) is the probability that a person has the flu. So P(B) = 0.1.

P(A/B) is the probability that a person has a runny nose, given that she has the flu. So P(A/B) = 0.99.

P(A) is the probability that a person has a runny nose. It is 0.99 of 0.1 and 0.90 of 0.90. So

$P(A) = 0.99*0.1 + 0.9*0.9 = 0.909$

What is the probability that this person has the flu?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.1*0.99}{0.909} = 0.1089 = 0.11$

The correct answer is:

E. 0.11

5 0

2 years ago

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$F (x) = x ^ 2
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We have then:
$y = (1/2) * x ^ 2
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Horizontal translations:
Suppose that h> 0
To graph y = f (x + h), move the graph of h units to the left.
We have then:
$y = (1/2) * (x + 3) ^ 2
$
Vertical translations:
Suppose that k> 0
To graph y = f (x) + k, move the graph of k units up.
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$h (x) = (1/2) * (x + 3) ^ 2 + 2
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