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3 years ago

I need help with this any help will be appreciated

Mathematics

1 answer:

Mars2501 [29]3 years ago

7 0

Are you trying to solve for x and y?

y=2x+1; x+2y=17
sub in one variable in the other equation.
x+2(2x+1)=17
x+4x+2=17
5x=15
x=3

now that you have x value, plug into the original equation to find y and check with the other.
y=2(3)+1 = 7
x+2y=17 = 3 + 2(7) = 17 ; 17=17

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What is the slope of the line that passes through the points ( 4 , 6 ) (4,6) and ( − 16 , − 18 ) ? (−16,−18

borishaifa [10]

Answer:

1.2

Step-by-step explanation:

Gradient = y2-y1/x2-x1

Coordinates = (4,6), (-16,-18)

-18 - 6/-16 - 4

-24/ -20

= 1.2

Hope it helps.

4 0

3 years ago

So Confused!! Somebody Plz Explain How To Do!!!!!!!

Anton [14]

Answer: A) 3x + 5x - 4 = 1

Step-by-step explanation:

The second equation is y + 4 = 5x. Solve this equation for y by subtracting 4 from both sides. --> y = 5x - 4

Now replace "y" in the first equation with "5x - 4".

3x + y = 1

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3 years ago

The population of Rock Springs is growing at a constant rate. The expression represents the increase in population in x years. 4

shusha [124]

The expression is given such as:
45, 200 + 1900x

We are asked to solve for the initial production, which means we have x = 0
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45, 200 + 1900*0
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8 0

3 years ago

Calculate the length of AC

Liono4ka [1.6K]

Answer:

Length of the side AC is 12 units.

Step-by-step explanation:

Here, in the triangle ABC

Base = 5 units

Let, Perpendicular = k units

Hypotenuse = 13 units

In a Right angle triangle, by PYTHAGORAS THEOREM:

$(Base)^{2} + (Perpendicular)^{2} = (Hypotenuse)^{2}$

Similarly, in triangle ABC

$(AB)^{2} + (AC)^{2} = (BC)^{2}$

or, $(5)^{2} + (k)^{2} = (13)^{2}$

⇒ $k^{2} = 169 - 25 = 144$

⇒ k = 12, or k= -12

But as k is the length of a side of a triangle so, k ≠ -12

⇒ k = 12

Hence, the length of the side AC = 12 units.

8 0

3 years ago

A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang

laiz [17]

Answer-

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

Solution-

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

$\binom{19}{3} = \frac{19!}{3!16!} = 969$

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

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