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poizon [28]
3 years ago
14

Which rule deacribes the

Mathematics
1 answer:
Marysya12 [62]3 years ago
6 0

Answer:

A. {T_{-6,-2}}\circ {r_{x-axis}}(x,y)

Step-by-step explanation:

We have that, ΔABC is transformed to get ΔA''B''C''.

We see that the following transformations are applied:

1. Reflection across x-axis i.e. flipped across x-axis.

Now, ΔABC is reflected across x-axis along the line AC to get ΔA'B'C'.

2. Translated 2 units down i.e. shifted 2 units down and and then translated 6 units to the left i.e. shifted 6 units to the left.

So, ΔA'B'C' is translated 2 units downwards and 6 units to the left to get ΔA''B''C''.

Hence, the sequence of transformations is Reflection across x-axis and then Translation of 2 units down and 6 units left.

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Answer:

First option: As x⇒ ∞ f(x) ⇒ -∞.  As x⇒ -∞ f(x) ⇒ ∞.

Step-by-step explanation:

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This is a negative cubic function. The function decreases over the interval

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Find the area of a circle with radius 7 ft.
aivan3 [116]

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153.9 ft²

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3 years ago
Read 2 more answers
A cereal company is exploring new cylinder-shaped containers. Two possible containers are shown in the diagram.x is 6 and r=4.5
KatRina [158]

Answer:

Container \rm X will have less label area than container \rm Y by about 9\; \rm in.

Step-by-step explanation:

A rectangular sheet of paper can be rolled into a cylinder. Conversely, the lateral surface of a cylinder can be unrolled into a rectangle- without changing the area of that surface.

Indeed, the width of that rectangle will be the same as the height of the cylinder. On the other hand, the length of that rectangle should be exactly equal to the circumference of the circles on the top and the bottom of the cylinder. In other words, if a cylinder has a height of h and a radius of r at the top and the bottom, then its lateral surface can be unrolled into a rectangle of width h and length 2\,\pi\, r.

Apply this reasoning to both cylinder \mathrm{X} and \rm Y:

For cylinder \mathrm{X}, h = 6\; \rm in while r = 4.5\; \rm in. Therefore, when the lateral side of this cylinder is unrolled:

  • The width of the rectangle will be 6\; \rm in, while
  • The length of the rectangle will be 2 \, \pi \times 4.5\; \rm in = 9\, \pi\; \rm in.

That corresponds to a lateral surface area of 54\, \pi\; \rm in^2.

For cylinder \rm Y, h = 10.5\; \rm in while r = 3\; \rm in. Similarly, when the lateral side of this cylinder is unrolled:

  • The width of the rectangle will be 10.5\; \rm in, while
  • The length of the rectangle will be 2\pi\times 3\; \rm in = 6\,\pi \; \rm in.

That corresponds to a lateral surface area of 63\,\pi \; \rm in^2.

Therefore, the lateral surface area of cylinder \rm X is smaller than that of cylinder \rm Y by 9\,\pi\; \rm in^2.

5 0
3 years ago
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