Answer:
The tenth number in the list that gets output is 29
Explanation:
To get this done, the algorithm has to be implemented using a programming language;
The algorithm is translated to Python Programming Language as follows (Comment explains difficult lines);
#Declare an empty list
mylist = []
#Input n = 2 to 100 to list
for n in range(2,101):
mylist.append(n)
#Iterate from 2 to 50
for n in range(2,51):
#Initialize first multiple of n
k = 0
#Iterate multiples of n
for j in range(n,51,n):
k = k + 1
#Check if item exist
if j in mylist:
#Print multiples of n greater than n
if not k == 1:
mylist.remove(j)
#Print All List
print("List: ",mylist)
#Print 10th element of the list
print("10th Element: ",mylist[9])
After running the program, the output is as follows:
List: [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100]
10th Element: 29
