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Hoochie [10]
3 years ago
7

What is a 1 whole plus 2 over 5?

Mathematics
2 answers:
Mrac [35]3 years ago
5 0

Answer:

1 2/5

Step-by-step explanation:

2 over 5= 2/5

1 whole= 1/1

first you should get the two fractions to have a common denominator

the common denominator is 5

1/1 times 5/5= 5/5

now add 2/5 and 5/5

2/5+ 5/5= 7/5 or as mixed number it will be 1 2/5

Another way to do this is:

you could just write this as mixed fraction

think that  2/5 is 0 2/5

just add the 1 to 0, so the answer is 1 2/5

Burka [1]3 years ago
4 0

We can write this as 1 + 2/5

= 5/5 + 2/5 (1 is the same as 5/5)

= 7/5 or 1 2/5

Best of Luck!

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Point G is on line segment FH. Given FG=5x+2,GH=3x-1, and FG=9, determine the numerical length of FG
stealth61 [152]

Given:

FG=5x+2

GH=3x-1

FG=9

Let us draw the line segment as follows,

Equating the length of FG, we get,

\begin{gathered} 5x+2=9 \\ 5x=9-2 \\ 5x=7 \\ x=\frac{7}{5} \end{gathered}

Substitute the value of x in the given value of GH,

\begin{gathered} GH=3x-1 \\ =3(\frac{7}{5})-1 \\ =\frac{21}{5}-1 \\ =\frac{16}{5} \\ =3.2 \end{gathered}

And the total length FH is,

\begin{gathered} FH=FG+GH \\ =9+3.2 \\ =12.2 \end{gathered}

Hence, the lengths are,

\begin{gathered} FG=9 \\ GH=3.2 \\ FH=12.2 \end{gathered}

8 0
1 year ago
HELP!!! ASAP!
Feliz [49]

The solution to given system of equations is (x, y) = (\frac{-15}{263} , \frac{-115}{263})

The given equation has one solution

<em><u>Solution:</u></em>

Given system of equations are:

12x - 13y = 5 --------- eqn 1

x = 23y + 10 --------- eqn 2

We have to solve the system of equations by substitution

<em><u>Substitute eqn 2 in eqn 1</u></em>

12(23y + 10) - 13y = 5

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263y = 5 - 120

263y = -115

y = \frac{-115}{263}

<em><u>Substitute the above value of "y" in eqn 2</u></em>

x = 23 \times \frac{-115}{263} + 10\\\\x = \frac{-2645}{263} + 10\\\\x = \frac{-2645 + 2630}{263}\\\\x = \frac{-15}{263}

Thus the solution to given system of equations is (x, y) = (\frac{-15}{263} , \frac{-115}{263})

Thus the given equation has one solution

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Step-by-step explanation:

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