Answer:
0.1875, or 3/16
Step-by-step explanation:
The formula for density is mass/volume.
I hope this helps :)
Given:
The graph of a function 
.
To find:
The interval where 
.
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, for 
and 
.
The function between x=0 and x=3.6 lies below the x-axis. So, 
for 
.
Now,
For 
, the graph of h(x) is above the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
Only for the interval , we get .
Therefore, the correct option is A.
Answer:
= 0.714 (in decimal fraction)
The probability that the death in 2014 was not caused by heart diseases or Unintentional Injuries = 0.714
= 0.714
Step-by-step explanation:
Let's interpret the question our way ti solve it .
Total deaths in 2014:
2626418
Death caused by Heart Diseases:
614348
Death caused by Unintentional Injuries:
750401
Therefore, we can deduced that, the number of death not caused by Heart Diseases or Unintentional Injuries = Total deaths in 2014 minus sum of the recorded death.
= 2626418 - ( 614348 + 136053)
= 2626418 - 750401
= 1876017.
Now, the probability that there were death in 2014 is 1 (one)
To find the probability that death we're not caused by heart diseases or Unintentional Injuries:
= 1 - Pr (Death Caused by heart diseases) + Pr (Death causes by Unintentional Injuries)
= 1 - (0.234 + 0.052)
= 1 - 0.286
= 0.714
To Check:
= 1876017 / 2626418
Divide to the lowest term
=0.714
Thee correlation factor formula for two variables is
(r) =[ nΣxy – (Σx)(Σy) / Sqrt([nΣx^2 – (Σx)^2][nΣy^2 – (Σy)^2])].
A). as per the formula the correlation factor for the given data is 0.94.
B). the month of September has the highest correlation as 0.94 is much closer to 1 than 0.89.( note: 1 denotes the perfect correlation and 0 denotes no correlation at all)
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Answer:
1) Subtracting one from the other
2) x = 0.375 and y = 0.125
Step-by-step explanation:
Equation 1 :
Equation 2:
To solve these equations by the Elimination method we multiply equation 1 with 6 and multiply equation 2 with 2 so now,
Now for the second equation:
Now subtracting equation 2 from equation 1
now insert this value of y into any equation
lets insert it into equation 1
