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Karo-lina-s [1.5K]
3 years ago
7

You travel 224 miles in 4 hours. What is the unit rate? Please help its math!

Mathematics
2 answers:
aalyn [17]3 years ago
8 0

Answer:

56

Step-by-step explanation:

I am being honest here I am not sure if it is the answer but what I did is divided 224 by 4 to get the unit rate

GenaCL600 [577]3 years ago
7 0
It would be 56 mph. you need to divide 224 from 4 to get the unit rate
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I think the answer is b B. y = negative 2 over 3x − 7
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3 years ago
Which of the following is an asymptote of y = sec(x)?
babunello [35]
Answer: option d. x = 3π/2

Solution:

function y = sec(x)

1) y = 1 / cos(x)

2) When cos(x) = 0, 1 / cos(x) is not defined

3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...

4) limit of sec(x) = lim of 1 / cos(x).

When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.

So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).

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The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).

8 0
3 years ago
Read 2 more answers
Can anyone solve this? If so tell me and make sure u know what ur doing please
raketka [301]

Answer:

-2

Step-by-step explanation:

To find the slope of a line, you need to find the \frac{rise}{run} between two points. I will be using the points (-3, 2) and (-1, -2).

\frac{rise}{run} = \frac{-2-2}{-1-(-3)}

     = \frac{-2-2}{-1+3}

     = \frac{-4}{2}

     = -2

6 0
3 years ago
A group of students are asked to evaluate their teacher mid-quarter
Umnica [9.8K]

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Step-by-step explanation:

The source of bias that occurs when a group of students are asked to evaluate their teacher mid-quarter is a perceived lack of anonymity.

Perceived lack of anonymity occurs when the responder is afraid that if he or she gives an honest answer, it can end up affecting them negatively.

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7 0
3 years ago
HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270
BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

\large \boxed{sin \theta = tan \theta cos \theta} \\  \large \boxed{tan^{2}  \theta + 1 =  {sec}^{2} \theta}

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

\large{ {4}^{2}  + 1 =  {sec}^{2} \theta } \\  \large{16 + 1 =  {sec}^{2} \theta } \\  \large{ {sec}^{2}  \theta = 17}

As we know, sec²θ = 1/cos²θ.

\large \boxed{sec \theta =   \frac{1}{cos \theta} } \\  \large \boxed{ {sec}^{2}  \theta =  \frac{1}{ {cos}^{2}  \theta} }

And thus,

\large{  {cos}^{2}  \theta =  \frac{1}{17}}   \\ \large{cos \theta =  \frac{ \sqrt{1} }{ \sqrt{17} } } \\  \large{cos \theta =  \frac{1}{ \sqrt{17} }  \longrightarrow  \frac{ \sqrt{17} }{17} }

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

\large{cos \theta =   \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta =  -  \frac{ \sqrt{17} }{17}}

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

\large{sin \theta = 4 \times ( -  \frac{ \sqrt{17} }{17}) } \\  \large{sin \theta =  -  \frac{4 \sqrt{17} }{17} }

Answer

  • sinθ = -4sqrt(17)/17 or A choice.
4 0
3 years ago
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