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Kay [80]
4 years ago
15

Complex numbers & DeMoivre's theory If z=-1-√3 i and z^6=a+bi, a=_____ and b=_____

Mathematics
1 answer:
Mice21 [21]4 years ago
8 0

Convert z to exponential/polar/trigonometric form:

r=|z|=\sqrt{(-1)^2+(-\sqrt 3)^2}=2

\tan\theta=\dfrac{-\sqrt3}{-1}\implies\theta=\dfrac{4\pi}3

\implies z=-1-\sqrt3\,i=2e^{4\pi/3\,i}=2\left(\cos\dfrac{4\pi}3+i\sin\dfrac{4\pi}3\right)

By DeMoivre's theorem,

z^6=\left(2e^{4\pi/3\,i}\right)^6=2^6e^{24\pi/3\,i}=64e^{8\pi\,i}

z^6=64\left(\cos8\pi+i\sin8\pi)=64

so that a=64 and b=0.

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