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GarryVolchara [31]
3 years ago
10

Mr. Barclay sold goods for $21 and lost a percent equal to the number of dollars he paid for the goods. How much did the goods c

ost him?
Mathematics
1 answer:
Marat540 [252]3 years ago
5 0
The goods cost him 21 dollars
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the front of a tent is an equilateral triangle with the ratio of its base b toits height h given by b/h+2/3 rewrite the equation
kap26 [50]

Answer:

h = b(√3)/2

Step-by-step explanation:

The ratio of base to height of an equilateral triangle is ...

... b/h = 2/√3

Multiplying both sides of the equation by (√3)h/2, we get

.. h = b(√3)/2 . . . . . . your equation with h as the subject

8 0
3 years ago
A diameter of a circle has endpoints p(-10,-2) and Q(4,6)
hodyreva [135]

Answer:

a. (-3,2)

b. sqrt65

c.

Step-by-step explanation:

a. To find the center of the circle, you can think of it just like finding the midpoint between the two endpoints. To find a midpoint between two endpoints, you take the average of the x values to get the x coordinate, and you take the average of the y values to get the y coordinate of the midpoint. Therefore, if (-10, -2) is (x1, y1) and (4, 6) is (x2, y2), the midpoint/center of the circle would be:

( (x1+x2)/2, (y1+y2)/2 ). When you plug in our x and y values, you get (-3, 2).

b. To find the radius of a circle, you need to know the center/midpoint of the circle which we solved for in part a. The formula for finding the radius of a circle with the center is (x-h)^2 + (y-k)^2 = r^2 for (h, k) as the center. The coordinates of the center that we found earlier for this circle are (-3, 2). With that, we just plug in our numbers into the formula, and we get:

(x+3)^2 + (y-2)^2 = r^2. Now, to get r, we can choose one of the original two endpoints given and plug in the x and y coordinates from that point into this equation. I like (4, 6), so I'm going to plug in 4 for x and 6 for y, and so we get (4+3)^2 + (6-2)^2 = r^2 which equals 49 + 16 = r^2 when simplified. 49 plus 16 is equal to 65, so we get 65 = r^2. To finally get r, we square root both sides of the equation to get r =  sqrt65 which is already in the simplest radical form.

c. The circle equation is (x-h)^2 + (y-k)^2 = r^2, like I said in part b. Therefore, we already have our circle equation! We just plug in our center points and we get (x+3)^2 + (y-2)^2 = sqrt65. This is usually an equation a question will give you for a circle, and with this information, they will expect you to find the center (h, k) or the circle and it's radius, r.

4 0
3 years ago
Please help me for number 1
Kruka [31]
So 1st.
50-34.56
do ur math problem thing to get 15.44
then, just use least amount of bills.
so a $10 bill, a $5 bill, a quarter, a dime, a nickle, and 4 pennies.
3 0
3 years ago
Which of these points is the closest to the point (7, 1) ?
pantera1 [17]

Step-by-step explanation:

Solution

The general equation of the plane passing through (2,5,−3) is

a(x−2)+b(y−5)+c(z+3)=0 .........(1)

Now, this plane passes through B(−2,−3,5) and C(5,3,−3).Then we have

a(−2−2)+b(−3−5)+c(5+3)=0

⇒−4a−8b+8c=0

⇒−a−2b+2c=0 ..........(2)

a(5−2)+b(3−5)+c(−3+3)=0

⇒3a−2b=0 ..........(3)

Solving (2) and (3) we get

0+4

a

=

6−0

b

=

2+6

c

⇒

4

a

=

6

b

=

8

c

=λ(say)

⇒a=4λ,b=6λ,c=8λ

Substituting the values of a,b and c in (1), we get

4λ(x−2)+6λ(y−5)+8λ(z+3)=0

⇒4(x−2)+6(y−5)+8(z+3)=0

⇒4x+6y+8z−14=0

⇒2x+3y+4z−7=0

This is the equation of the plane determined by the points A(2,5,−3),B(−2,−3,5) and C(5,3,−3)

Now, the distance of this plane from the point (7,2,4) is

D=

2

2

+3

2

+4

2

∣(2×7+3×2+4×4)−7∣

=

4+9+16

∣(14+6+16)−7∣

=

4+9+16

∣36−7∣

=

29

29

=

29

29

×

29

29

=

29

units.

Thus, the distance between the point (7,2,4) and the plane 2x+3y+4z−7=0 is

29

units.

8 0
3 years ago
What is the awnser to this if you get it right I will mark you
Pavel [41]

I think it's D. 48 ft²

because 8 × 6 is 48

5 0
3 years ago
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