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Maslowich
3 years ago
14

Help me plz 2 _ Y + 7 = 15 3

Mathematics
1 answer:
julia-pushkina [17]3 years ago
7 0

Answer:

y= 12

Step-by-step explanation:

2/3 y + 7 = 15

Subtract 7 from each side

2/3 y + 7-7 = 15-7

2/3 y = 8

Multiply each side by 3/2 to isolate y

3/2 * 2/3 y = 3/2 * 8

3/2 * 2/3 y = 3 * 4

y = 12

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The average of six weights is 12 kilograms. Another weight of 5 kilograms is added to the scale. What is the average of the seve
Anastaziya [24]

Answer:

Hi there! Your answer here is 11kg - the average of the seven weights is 11kg. To find the average of a group of numbers, you add all of the numbers (12, 12, 12, 12, 12, 12, 5), then divide by the count of those numbers (7).

12 + 12 + 12 + 12 + 12 + 12 + 5 (or 12*6 + 5) is equal to 77.

77 / 7 = 11.

So the average of the seven weights is 11kg.

Have a great day! - Mani :)

5 0
3 years ago
What's the answer please and thank you ​
topjm [15]

Where's the question??

7 0
4 years ago
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Item 5
sveticcg [70]

Answer:

$94.50

Step-by-step explanation:

6 0
3 years ago
In a certain population, body weights are normally distributed with a mean of 152 pounds 30) and a standard deviation of 26 poun
Paul [167]

We are given the following variables:

μ = the sample mean = 152 pounds

σ = the standard deviation = 26 pounds

x = the sample value we want to test = 180 pounds

n = the sample size = unknown

MOE = margin of error = 4% = 0.04

Confidence level = 96%

 

The first thing we can do is to find for the value of z using the formula:

z = (x – μ) / σ

z = (180 – 152) / 26

z = 1.0769 = 1.08

Since we are looking for the people who weigh more than 180 pounds, therefore this is a right tailed z test. The p value is:

p = 0.1401

 

Then we can use the formula below to solve for n:

n = z^2 * p * (1 – p) / (MOE)^2

n = 1.08^2 * 0.1401 * (1 – 0.1401) / (0.04)^2

n = 87.82 = 88

 

Therefore around 88 people must be surveyed.

8 0
4 years ago
Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
olganol [36]

Answer:

B or D

Step-by-step explanation:

your x point with be really close to 0 but not quite zero while your y would be 3

8 0
3 years ago
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