Question

In △ABC, AB = 7 and AC = 17. Find m∠B to the nearest degree 68 38 21 87

Answer 1

Answer:

The m∠B is 68°

Step-by-step explanation:

Given the right angled triangle ABC in which right angled is at A.

AB = 7 units and AC = 17 units

we have to find the measure of ∠B.

By trigonometric ratios,

$cot \angle B=\frac{AB}{AC}$

$cot \angle=\frac{7}{17}$

$\angle B=cot^{-1}(\frac{7}{17})$

$\angle B=67.619864948\sim 68^{\circ}$

Hence, the m∠B is 68°

Option 1 is correct

Answer 2

I believe it is 68 degrees