Answer:
Money raised by each team = 94 + 11 = <em>$105</em>
Number of cars washed = <em>11</em>
Step-by-step explanation:
Money already present with volleyball team = $50
Money raised by washing each car by volleyball team = $5
Let the number of cars washed = 
Money raised by washing cars = $5
Money already present with volleyball team = $94
Money raised by washing each car by volleyball team = $1
Money raised by washing cars = $1 = $
Given that, both the teams have raised same amount of money:
Money raised by each team = 94 + 11 = <em>$105</em>
Number of cars washed = <em>11</em>
Answer:
30?
Step-by-step explanation:
divide 20 by 8 and then times the answer by 12
Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
An example would be money! Money is a real life situation
