Answer:
m<SQP=124°
Step-by-step explanation:
Hi there!
We're given ΔQRS, the measure of <R (90°), and the measure of <S (34°)
we need to find m<SQP (given as x+72°)
exterior angle theorem is a theorem that states that an exterior angle (an angle on the OUTSIDE of a shape) is equal to the sum of the two remote interior angles (the angle OUTSIDE of a shape will be equal to the sum of 2 angles that are OPPOSITE to that angle).
that means that m<SQP=m<R+m<S (Exterior angle theorem)
substitute the known values into the equation
x+72°=90°+34° (substitution)
combine like terms on both sides
x+72°=124° (algebra)
subtract 72 from both sides
x=52° (algebra)
however, that's just the value of x. Because m<SQP is x+72°, add 52 and 72 together to get the value of m<SQP
m<SQP=x+72°=52°+72°=124° (substitution, algebra)
Hope this helps!
We just need to know the sin 40 value
It would round up to 31 because the decimal place is greater than 5
What is B? We cannot help you if we do not know what B is.
Answer:
C
Step-by-step explanation:
< open circle, not ≤
