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3 years ago

What is Naptha used for?

Computers and Technology

2 answers:

denis-greek [22]3 years ago

7 0

Answer:

Naphtha is used to dilute heavy crude oil to reduce its viscosity and enable/facilitate transport; undiluted heavy crude cannot normally be transported by pipeline, and may also be difficult to pump onto oil tankers. Other common dilutants include natural-gas condensate, and light crude.

Sidana [21]3 years ago

5 0

Answer:

Naphtha is used for laundry soaps and clearing fluids

High Hopes^^

Barry-

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You are a psychologist who needs to provide a qualitative evaluation for IQ scores. Create a program that takes IQ scores (one a

dsp73

Answer:

Check the explanation

Explanation:

#include <iostream>

#include <iomanip>

using namespace std;

int getIQ(); // return the score

void printEvaluation(int);

int main()

{

int IQ = 0;

IQ = getIQ();

printEvaluation(IQ);

return 0;

}

int getIQ()

{

int score = 0;

cout << "Please enter your IQ Score to receive your IQ Rating:\n";

cin >> score;

return score;

}

void printEvaluation(int aScore)

{

cout << "IQ Score: " << aScore << " IQ Rating: ";

if (aScore <= 100)

{

cout << "Below Average\n";

}

else if (aScore <= 119)

{

cout <<"Average\n";

}

else if (aScore <= 160)

{

cout << "Superior\n";

}

else if (aScore >= 160 )

{

cout << "Genius\n";

}

4 0

3 years ago

Project 15A - Math Application

vovikov84 [41]

Answer:

A simple php code for the following is given below:

Explanation:

interface Calculate {

public function area($lenght,$width);

public function perimeter($length,$width);

public function surfaceArea($length_side_1,$length_side_2);

public funcction volume($length, $width, $height):

}

interface Calculate2 {

public function area($raidus);

public function perimeter($radius);

public function surfaceArea($radius);

public funcction volume($radius):

}

Class Mian{

width=please Enter the value of width

height=please Enterr the value of height

length=please enter the value of length

lenght2=please enter the value of lenth of side 2

ridus= please enter the value of radius

Circle = new circle()

Rectangle = new rectangle()

}

Class Circle implements Calculate2{

public function area(){

area= pi*r

return area

}

public function perimeter(){

perimeter=2*pi*r

return perimeter

}

public function surfaceArea(){

surfacearea= pi*r*r

}

public function volume(){}

area=area()

volume=area*height

return volume

}

Class Rectangle implements Calculate{

public function area(lenght,width){

area= length * width

return area

}

public function perimeter(lenght,width){

perimenter=2(lenght+width)

return perimeter

}

public function surfaceArea(length_side_1, withd right place){}

surface_area 2*length_side_1 f* length_side_2_

public function volume(){}

public surface volume(length,width,height)

volume= length * width * height

return volume

}

7 0

3 years ago

What is the primary responsibility of the physical layer in data communication?

melamori03 [73]

It is responsible for transmitting these bits as signals over a wire, optical fiber, wireless, or other medium.

3 0

3 years ago

Determine and prove whether an argument in English is valid or invalid. About Prove whether each argument is valid or invalid. F

yawa3891 [41]

Answer:

Each understudy on the respect roll got an A.

No understudy who got a confinement got an A.

No understudy who got a confinement is on the respect roll.

No understudy who got an A missed class.

No understudy who got a confinement got an A.

No understudy who got a confinement missed class

Explanation:

M(x): x missed class

An (x): x got an A.

D(x): x got a confinement.

¬∃x (A(x) ∧ M(x))

¬∃x (D(x) ∧ A(x))

∴ ¬∃x (D(x) ∧ M(x))

The conflict isn't considerable. Consider a class that includes a lone understudy named Frank. If M(Frank) = D(Frank) = T and A(Frank) = F, by then the hypotheses are overall evident and the end is counterfeit. Toward the day's end, Frank got a control, missed class, and didn't get an A.

Each understudy who missed class got a confinement.

Penelope is an understudy in the class.

Penelope got a confinement.

Penelope missed class.

M(x): x missed class

S(x): x is an understudy in the class.

D(x): x got a confinement.

Each understudy who missed class got a confinement.

Penelope is an understudy in the class.

Penelope didn't miss class.

Penelope didn't get imprisonment.

M(x): x missed class

S(x): x is an understudy in the class.

D(x): x got imprisonment.

Each understudy who missed class or got imprisonment didn't get an A.

Penelope is an understudy in the class.

Penelope got an A.

Penelope didn't get repression.

M(x): x missed class

S(x): x is an understudy in the class.

D(x): x got a repression.

An (ax): x got an A.

H(x): x is on the regard roll

An (x): x got an A.

D(x): x got a repression.

∀x (H(x) → A(x)) a

¬∃x (D(x) ∧ A(x))

∴ ¬∃x (D(x) ∧ H(x))

Real.

1. ∀x (H(x) → A(x)) Hypothesis

2. c is a self-self-assured element Element definition

3. H(c) → A(c) Universal dispatch, 1, 2

4. ¬∃x (D(x) ∧ A(x)) Hypothesis

5. ∀x ¬(D(x) ∧ A(x)) De Morgan's law, 4

6. ¬(D(c) ∧ A(c)) Universal dispatch, 2, 5

7. ¬D(c) ∨ ¬A(c) De Morgan's law, 6

8. ¬A(c) ∨ ¬D(c) Commutative law, 7

9. ¬H(c) ∨ A(c) Conditional character, 3

10. A(c) ∨ ¬H(c) Commutative law, 9

11. ¬D(c) ∨ ¬H(c) Resolution, 8, 10

12. ¬(D(c) ∧ H(c)) De Morgan's law, 11

13. ∀x ¬(D(x) ∧ H(x)) Universal hypothesis, 2, 12

14. ¬∃x (D(x) ∧ H(x)) De Morgan's law, 13

4 0

3 years ago

Please help!! will fan and medal

levacccp [35]

So here are the answers that would best complete the given statements above.
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7 0

4 years ago

Read 2 more answers