All categories

2 years ago

9x + 7 < 8x - 2 HELPPPPPPPP

Mathematics

2 answers:

-Dominant- [34]2 years ago

7 0

Step by Step Solution:

Rearrange:

Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :

9*x-7-(8*x-2)<0

Step by step solution :

STEP

1 : Solve Basic Inequality :

1.1 Add 5 to both sides

x < 5

Inequality Plot :

1.2 Inequality plot for

x - 5.000 < 0

One solution was found :

x < 5

konstantin123 [22]2 years ago

4 0

Answer:

x< -9

Step-by-step explanation:

9x-8x<-2-7

x< -9

You might be interested in

What are the answers to these 3 problems?

sesenic [268]

The first is the first one tho

3 0

2 years ago

Can someone solve this for me????? (10−523)⋅(−2)+x=823

AleksandrR [38]

Answer:The answer is x = -203.

Step-by-step explanation:

1. reduce brackets

2. reduce 10 - 523 to -513

3. reduce -513 x -2 to 1026

4. subtract 1026 from both sides

5. reduce 823 - 1026 to -203

3 0

3 years ago

(4x-3)-(x+6)<br> simplify

zzz [600]

Answer:

3x-9

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Which line segment shows the height that corresponds to the given base of the triangle btw it isnt high school

pickupchik [31]

Answer:

Step-by-step explanation:

The height has to be perpendicular ( 90 degrees) to the base

B is the height to the base

6 0

3 years ago

Find the general solution of the following equation. Express the solution explicitly as a function of the independent variable.

Mashcka [7]

Answer:

Therefore the general solution is

$2 \sqrt w = 2 ln(x) - 5 \frac1x +c$

Step-by-step explanation:

Integration Rule:

$\int x^n dx= \frac{x^{n+1}}{n+1}+c$
$\int \frac1x dx= ln(x) +c$

Given differential equation is

$x^2 \frac{dw}{dx}= \sqrt{w}(2x+5)$

$\Rightarrow x^2 dw= \sqrt{w} (2x+5) dx$ [ multiplying dx both sides]

$\Rightarrow \frac{dw}{\sqrt w}= \frac{(2x+5)}{x^2} dx$ [ dividing $x^2\sqrt w$ both sides]

Integrating both sides

$\int \frac{dw}{\sqrt w}=\int \frac{(2x+5)}{x^2} dx$

$\Rightarrow \int w^{-\frac12} dw=\int (\frac{2x}{x^2}+\frac{5}{x^2} )dx$

$\Rightarrow \int w^{-\frac12} dw=\int \frac{2}{x}dx +\int\frac{5}{x^2} dx$

$\Rightarrow \frac{w^{-\frac12+1}}{-\frac12+1} =2ln x+5 \frac{x^{-2+1}}{-2+1}+c$ [ c is arbitrary constant]

$\Rightarrow 2 \sqrt w = 2 ln(x) - 5 \frac1x +c$

Therefore the general solution is

$2 \sqrt w = 2 ln(x) - 5 \frac1x +c$

6 0

2 years ago