Simplify the expression below. (2n/6n+4)(3n+2/3n-2)What is the numerator of the simplified expression?
2 answers:
Answer:
n
Step-by-step explanation:
We see that in the first rational expression, both the numerator and denominator are divisible by 2. This means we can factor a 2 out of the top and bottom and then cancel it:
Now we can multiply straight across:
Since we have the same factor on the top and bottom, this factor cancels:
The numerator is n.
(2n/6n+4)(3n+2/3n-2) =2n(3n+2)/(6n+4)(3n-2) =(6n^2 + 4n)/(18n^2 - 12n + 12n -8) =(6n^2 + 4n)/(18n^2 - 8) =2(3n^2 + 2n)/2(9n^2 - 4) =(3n^2 + 2n)/(9n^2 - 4) =n(3n+ 2)/(3^2 × n^2 - 2^2) =n(3n+ 2)/(3n-2)(3n+2) =n/(3n-2) Answer:The numerator of the simplified expressions is n.
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= </span><span>| -1728 ÷ 196 |
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