The solution is:A mole of gas occupies 22.4 L A liter is 1000 cubic centimeters because 1 cubic centimeter = 1 mL
One Helium molecule (essentially one helium atom) has atomic mass 4 g/mol So for every 22400 cubic centimeters of volume, we have 4 grams of helium Density of helium = 4g / 22400 cm^3 = 1g / 5600 cm^3
Volume of a sphere = (4/3)(pi)r^3 Volume of the outside sphere (the entire sphere) is (4/3)(pi)(R+T)^3 Volume of the inside sphere (the hollow region) is (4/3)(pi)R^3
The difference for the volume of silver. (4/3)(pi)(R+T)^3 - (4/3)(pi)R^3 = (4/3)(pi)(3R^2T + 3RT^2 + T^3)
The density of silver is 10.5g/cm^3
So the mass of the silver is computed by:10.5*(4/3)(pi)(3R^2T + 3RT^2 + T^3) = (14*pi)(3R^2T + 3RT^2 + T^3) = (14pi)T(3R^2 + 3RT + T^2)
Now for the mass of helium: volume x density = (4/3)(pi)R^3 (1/5600) = (pi/4200)R^3
Set the two masses equal: (pi/4200)R^3 = (14pi)T(3R^2 + 3RT + T^2) R^3 = 58800*T(3R^2 + 3RT + T^2) R / T = 58800*(3R^2 + 3RT + T^2) / R^2 = 58800*( 3+T/R^2+(T/R)^2)
then solve for xx = T / R 1/x = 58800*( 3+x/R+x^2) 1/58800 = x (3 + x/R + x^2) 1/58800 = 3x + x^3 x^3 + 3x - 1/58800= 0 x = ~ 5.66893x10^(-6)
The answer is c. Because there inside and opposite
We already know that there are 12 sandwiches.
If there are 3 turkey and 5 veggie then there's 8 out of 12 sandwiches that aren't ham.
12 sandwiches - 8 non-ham sandwiches = 4 ham sandwiches
Now we know there are 4/12 ham sandwiches
We need to simplify this now.
4/12 can be divided by 4
4 goes into 4 1 time and 4 goes into 12 3 times making the answer 1/3
1/3 of the sandwiches are ham.
Answer:
f(x) = 54(two-thirds) Superscript x minus 1
Step-by-step explanation:
Given that:
First peak : 36 / 54=2/3
Second peak : 24 / 36 = 2/3
The common ratio here is 2/3 ; which mean each bounce height is 2/3 of previous height
Modeling this using geometric progression :
An=a1r^(n-1)
An = nth term of a geometric progression
a1=first term
r=common ratio = 2/3
n = nth term
a1=54
Substituting into the above formular :
An=54(2/3)^(n-1)
