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3 years ago

Write the equation of the graph shown below in factored form.

Mathematics

1 answer:

AURORKA [14]3 years ago

7 0

Look at where the red line crosses/ touches the X axis. This will give you the zeros.

It crosses at -1, it touches at 1 and crosses again at 3

This means the zeros are -1, 1 and 3

So you now you need to have (x+1) (x-3) and (x-1) as factors.

This makes the answer: f(x) = (x − 1)2(x + 1)(x − 3)

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Which expression is equivalent to -1.3-(-1.9)

alex41 [277]

-1.3+1.9=.6
the two minus signs turn into a plus so you add 1.9 to -1.3

7 0

3 years ago

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Find dy/dx of y=csc(square root of x)

Vitek1552 [10]

Answer:

$y' = -\dfrac{\cot x \csc x}{2 \sqrt{x}}$

Step-by-step explanation:

y = csc x

y' = -cot x csc x

$y = \csc \sqrt{x}$

$y' = \dfrac{d}{dx} [\csc \sqrt{x}]$

$y' = (-\cot x \csc x) \dfrac{d}{dx} \sqrt{x}$

$y' = (-\cot x \csc x) \dfrac{d}{dx} x^{\frac{1}{2}}$

$y' = (-\cot x \csc x) \dfrac{1}{2} x^{-\frac{1}{2}}$

$y' = -\dfrac{\cot x \csc x}{2 \sqrt{x}}$

5 0

3 years ago

Please help!!! this is due tomorrow!!1!!11!!!1!

Ronch [10]

Answer: m<KHL = 37 degrees.

m<GHK = 53 degrees

Step-by-step explanation:

<CHD and <KHL are vertical angles. They are equal in measure. m<CHD is 37 degrees, so m<KHL is also 37 degrees.

Notice <GHL is a 90 degree angle (because the lines that form it are perpendicular) and <GHL is made up of two angles: <GHK and <KHL.

m<GHK + m<KHL (37) = m< GHL (90 degrees)

Subtract 37 from both sides.

m<GHK = 53 degrees

7 0

3 years ago

Which function is shown in the graph below?

Helga [31]

Answer:

Step-by-step explanation:

I’m not entirely sure if this is right but I hope I helped.

8 0

3 years ago

Hence solve the equation x^3+x^2-6x=0

Aneli [31]

Answer:

x³ + x² - 6x = 0

x(x² + x - 6) = 0

x(x² + 3x - 2x - 6) = 0

x[x(x + 3) - 2(x + 3)] = 0

x(x - 2)(x + 3) = 0

x₁ = 0

x - 2 = 0 => x₂ = 2

x + 3 = 0 => x₃ = - 3

4 0

4 years ago

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