Answer:
x=-4
x=-5
Step-by-step explanation:
Answer:
x = 136/11
, y = 68/11
Step-by-step explanation:
Solve the following system:
{6 x - y = 68
2 y = x
Hint: | Choose an equation and a variable to solve for.
In the second equation, look to solve for x:
{6 x - y = 68
2 y = x
Hint: | Reverse the equality in 2 y = x in order to isolate x to the left hand side.
2 y = x is equivalent to x = 2 y:
{6 x - y = 68
x = 2 y
Hint: | Perform a substitution.
Substitute x = 2 y into the first equation:
{11 y = 68
x = 2 y
Hint: | Choose an equation and a variable to solve for.
In the first equation, look to solve for y:
{11 y = 68
x = 2 y
Hint: | Solve for y.
Divide both sides by 11:
{y = 68/11
x = 2 y
Hint: | Perform a back substitution.
Substitute y = 68/11 into the second equation:
{y = 68/11
x = 136/11
Hint: | Sort results.
Collect results in alphabetical order:
Answer: {x = 136/11
, y = 68/11
The volume is 12x20x10 then divide by 2
200x12=2400
2400/2= 1200
1.
no, there will never be a negative y-value. <span>y= |x| will always be nonnegative. |x| can be distance x is from 0 and a distance can never be negative.
</span>2.
you can define it as
y = |x| = x if x ≥ 0, -x if x < 0
absolute value can be
interpreted as a function that does not allow negative real numbers,
forcing them to be positive (leaving 0 alone). if the input x is more
than or equal 0, then x stays positive so there is no need to do
anything: "x if x ≥ 0".
if the input is less than 0, then it is an
negative number and needs a negative coefficient to negate the negative:
"-x if x < 0"
example: if x = -3, then it will take the "-x if x < 0" piece resulting in y = -(-3) = 3, which is what |-3| does
if x = 1, it will take the "x if x ≥ 0" piece and just have y = 1 which is what |1| does.
for x = 0, it will take the "x if x ≥ 0" and just have y = 0 which is what |0| does
