9514 1404 393
Answer:
1731 ft
Step-by-step explanation:
The tangent relation is useful in this problem.
Tan = Opposite/Adjacent
The height of the light is found to be ...
tan(11°) = height/(639 ft)
height = (639 ft)·tan(11°) . . . . . solve for height
Then the distance from the light to point B is ...
tan(3°) = height/(B distance)
B distance = height/tan(3°) = (639 ft)·tan(11°)/tan(3°) ≈ 2370 ft
Then the distance from point A to point B is ...
2370 ft -639 ft = 1731 ft . . . AB distance
Answer:
I don't understand what you are asking.
Step-by-step explanation:
-say in the situation "C" was "X"; angle ∠C and ∠D are supplementary angles so ∠D-180=∠C
-all triangle, angles sums =180° so ∠A+∠B+∠C=180
-if the triangle were to be a right triangle you could use 30,60,90 or 45,45,90 but you need to know the measure of one of 2 of the angles
Answer:
k
Step-by-step explanation:k
k
4+x=(4/3) x 4 — you multiply both sides by 4 to get rid of the fraction on the left.
4+x=16/3 — then simplify the fraction on the right
x = 1 1/3 — minus 4 from both sides to get x alone