Answer: By the end of meiosis, the resulting reproductive cells, or gametes, each have 23 genetically unique chromosomes. The recombination of chromosomes creates genetic diversity by allowing genes from each parent to intermix, resulting in chromosomes with a different genetic complement.
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Answer:
The genotype of parents for 6 exceptional cross was
Bb * bb
Result for crossing the black and white guinea pigs from the 6 exceptional cases.
Bb * bb
Bb, Bb, bb, bb
Explanation:
Here trait for black guinea is dominant over the trait for white guinea
There is a possibility that for remaining 6 crosses, the genotype of parents would be as follows
Black guinea pig - Bb
White guinea pig - bb
Now when these two genotypes are crossed the following offsprings are produced
Bb * bb
Bb, Bb, bb, bb
Thus, out of four offspring half of them are heterozygous black and remaining half of them are white in color.
Now if these black and white guinea pigs from the 6 exceptional cases with genotype Bb and bb are crossed respectively, then following offspring are produced
Bb * bb
Bb, Bb, bb, bb
Every three years ( every 36 months ) hope this helps!!!!
