Answer:
1. Five classes in the frequency distribution
2.The mid point of the third class is 24.5
3.The total number of frequency is 100
4.The relative frequency of the third class is (20/100=0.2)
5. We use n-1 because we are dealing with a sample data
6. The mean is 24.5
7. The value of the standard deviation is 11
Step-by-step explanation:
See attached picture for the solutions
Got your answer.
I drew it out on a digital drawing software I have.
Answer:
D
Step-by-step explanation:
I can’t give a step-by-step explanation but it’s D
Answer:
The given fraction
reduces to 
Step-by-step explanation:
Consider the given fraction 
We have to reduce the fraction to the lowest terms.
Consider numerator 
We can take x² common from both the term,
Thus, numerator can be written as
Given expression can be rewritten as ,

We can now cancel
from both numerator and denominator,


Thus, the given fraction
reduces to 
N.O = 4
N is midpoint of M.0
Meaning M.N also has to be 4
4+4= 8
N.P = 6
0.P = 2
8+ 2 = 10