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Maslowich
3 years ago
7

PLS HELP SHOW ALL YOUR WORKING OUT AND BRAINLIEST WILL BE AWARDED

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
7 0
That would be a=5.97cm

i attached the pic of the solution.

hammer [34]3 years ago
4 0

Answer:

5.97 cm  to 3 significant figures.

Step-by-step explanation:

The diameter of the circle will be equal to the length of the diagonal of the square.

Area = 56 = πr^2

r^2 = 56 / π

r = √(56 / π) =  4.222 cm

So the diameter = 8.444 cm.

This  is  = diagonal of the square so, by The Pythagoras Theorem:

x^2 + x^2 = 8.444^2     where x  is the side of the square.

x^2 = (8.444)^2 / 2

x^2 = 35.651

x =  5.971 cm

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Step-by-step explanation:

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Afina-wow [57]
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Read 2 more answers
A statistics practitioner determined that the mean and stan-dard deviation of a data set were 90 and 15, respectively. What can
jasenka [17]

Answer:

If the distribution is bell shaped we can approximate the probability with high accuracy using the z score formula.

a) P(75

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(75

b) P(60

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(60

c) P(45

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(45

If the distribution is NOT bell shaped the approximation with the z score NOT works and we need to have the distribution for X in order to find the probabilities.

Step-by-step explanation:

Previous concepts

If the distribution is bell shaped we can approximate the probability with high accuracy using the z score formula.

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable of interest

We assume for this case that \mu=90 and \sigma=15

We are interested on this probability

P(75

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(75

Part b

P(60

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(60

Part c

P(45

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(45

If the distribution is NOT bell shaped the approximation with the z score NOT works and we need to have the distribution for X in order to find the probabilities.

5 0
4 years ago
1. Truncate the following numbers to the unit:<br> a) 25<br> b) 76<br> c) 10
deff fn [24]

Answer:

1 Truncation

Truncation is a method of approximating numbers. It is easier than rounding, but does not always give the best approximation to the original number. Truncation is used in computing when division is done with integers and the answer must be an integer.

Step-by-step explanation:

6 0
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