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saveliy_v [14]
3 years ago
13

The sum of two consecutive integers is − 17 -17. find the numbers

Mathematics
1 answer:
UkoKoshka [18]3 years ago
4 0
I think it might be -76
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List the integers that satisfy both these inequality. 2x+9<0 x>-12
Ludmilka [50]

Answer:

<u>Given:</u>

  • 2x + 9 < 0 ⇒ 2x < - 9 ⇒ x < - 4.5
  • x > -12

<u>Combined we have:</u>

  • -12 < x < - 4.5

<u>The integers in the same interval are:</u>

  • x ∈ {-11, -10, -9, -8, -7, -6, -5}
6 0
3 years ago
Simplify (2 3/5) divided ( -3 3/4)
Ostrovityanka [42]

Flip over the second fraction

2 3/5= 13/5 ( Multiply the whole number with the denominator, 2*5=10 then add the numerator 10+3=13

-3 3/4= -15/4

13/5 * -4/15= -52/75

Answer :-52/75

4 0
4 years ago
Jerry bought 9 gallons of gasoline for “D” dollars per gallon. Steve purchased the same amount of gasoline, but at a price that
katrin2010 [14]

Answer: 1.17

Step-by-step explanation: multiply 9 x 0.13

6 0
4 years ago
Surveys indicate that 5% of the students who took the SATs had enrolled in an SAT prep course. 30% of the SAT prep students were
zloy xaker [14]

Answer:

The required probability is 0.927

Step-by-step explanation:

Consider the provided information.

Surveys indicate that 5% of the students who took the SATs had enrolled in an SAT prep course.

That means 95% of students didn't enrolled in SAT prep course.

Let P(SAT) represents the enrolled in SAT prep course.

P(SAT)=0.05 and P(not SAT) = 0.95

30% of the SAT prep students were admitted to their first choice college, as were 20% of the other students.

P(F) represents the first choice college.

The probability he didn't take an SAT prep course is:

P[\text{not SAT} |P(F)]=\dfrac{P(\text{not SAT})\cap P(F) }{P(F)}

Substitute the respective values.

P[\text{not SAT} |P(F)]=\dfrac{0.95\times0.20 }{0.05\times0.30+0.95\times0.20}

P[\text{not SAT} |P(F)]\approx0.927

Hence, the required probability is 0.927

6 0
3 years ago
What is the answer 596.65x12 really need the answer
Mamont248 [21]
596.65 * 12 = 7,159.8
6 0
3 years ago
Read 2 more answers
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