Answer:
<u>Given:</u>
- 2x + 9 < 0 ⇒ 2x < - 9 ⇒ x < - 4.5
- x > -12
<u>Combined we have:</u>
<u>The integers in the same interval are:</u>
- x ∈ {-11, -10, -9, -8, -7, -6, -5}
Flip over the second fraction
2 3/5= 13/5 ( Multiply the whole number with the denominator, 2*5=10 then add the numerator 10+3=13
-3 3/4= -15/4
13/5 * -4/15= -52/75
Answer :-52/75
Answer: 1.17
Step-by-step explanation: multiply 9 x 0.13
Answer:
The required probability is 0.927
Step-by-step explanation:
Consider the provided information.
Surveys indicate that 5% of the students who took the SATs had enrolled in an SAT prep course.
That means 95% of students didn't enrolled in SAT prep course.
Let P(SAT) represents the enrolled in SAT prep course.
P(SAT)=0.05 and P(not SAT) = 0.95
30% of the SAT prep students were admitted to their first choice college, as were 20% of the other students.
P(F) represents the first choice college.
The probability he didn't take an SAT prep course is:
![P[\text{not SAT} |P(F)]=\dfrac{P(\text{not SAT})\cap P(F) }{P(F)}](https://tex.z-dn.net/?f=P%5B%5Ctext%7Bnot%20SAT%7D%20%7CP%28F%29%5D%3D%5Cdfrac%7BP%28%5Ctext%7Bnot%20SAT%7D%29%5Ccap%20P%28F%29%20%7D%7BP%28F%29%7D)
Substitute the respective values.
![P[\text{not SAT} |P(F)]=\dfrac{0.95\times0.20 }{0.05\times0.30+0.95\times0.20}](https://tex.z-dn.net/?f=P%5B%5Ctext%7Bnot%20SAT%7D%20%7CP%28F%29%5D%3D%5Cdfrac%7B0.95%5Ctimes0.20%20%7D%7B0.05%5Ctimes0.30%2B0.95%5Ctimes0.20%7D)
![P[\text{not SAT} |P(F)]\approx0.927](https://tex.z-dn.net/?f=P%5B%5Ctext%7Bnot%20SAT%7D%20%7CP%28F%29%5D%5Capprox0.927)
Hence, the required probability is 0.927