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xxMikexx [17]
2 years ago
10

Solve the following systems of equations without graphing 5x + 10y = 30 -5x +15y = 20

Mathematics
1 answer:
galben [10]2 years ago
8 0

Answer:

(2, 2)

Step-by-step explanation:

In this case, elimination would be the most efficient means of solving.

Simply, add the two equations, and you will be left with only one variable to solve for. (In this case y) You are then able to take your solution and plug it into an equation and solve for x, therefore giving you their intercept.\

5x + 10y = 30

+

-5x + 15y = 20

(x's cancel) 25y = 50

25y = 50

y = 2

5x + 10(2) = 30

5x + 20 = 30

5x = 10

x = 2

The solution to this equation is (2, 2)

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Vugar has a maximum of 30 batteries for toys. Each toy helicopter uses the same number of batteries, and each toy car uses the s
Leno4ka [110]

Answer: 3H+4C<_ 30

The coefficients of the variables H and C represent the number of batteries each toy helicopter and each toy car uses.

Step-by-step explanation:

Each toy helicopter uses 3 batteries, and each toy car uses 4 batteries.

Now let's check whether Vugar has enough batteries for 5 toy helicopters and 4 toy cars. To do this, we substitute  H=5 and C= 4 in the given inequality:

Does Vugar have enough batteries to play with 5 toy helicopters and 4 toy cars?

No, because if you plug in the value for H and C:

3H + 4C<_ 30

3(5) + 4(4) <_30

15 + 16 <_ 30

31 <_ 30; false

Since the inequality is false, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.

Each toy helicopter uses 333 batteries, and each toy car uses 444 batteries.

No, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.

6 0
3 years ago
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Kenny is packing cans into bags at the food bank he cn pack 8 cans into each bag how many bags how many bags will kenny need for
Sholpan [36]
1056cans/ 8 cans=132 bags
3 0
2 years ago
17. The area of a rectangular sandbox is 8x2 + 18x + 9. If one of it's dimensions is (2x + 3), what is the other
Natasha2012 [34]

Answer:

The other dimension of the sandbox must be (4x+3).

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2 years ago
The prices of three t-shirts styles are $24, $30 and $36. the probability of choosing a $24 t-shirt is 1/6. the probability of c
Slav-nsk [51]

\text{Answer} : \text{The expected value of a t-shirt is \$31.}

Explanation:

Since we have given that

The prices of three t-shirts styles  i.e $24, $30, $36 with their probability is given by

\frac{1}{6}, \frac{1}{2},\frac{1}{3}

As we know that,

E(X)= \sum_{1}^{3}x_iP(x_i)

\text{where} x_i \text{ is the prices of t- shirts styles}

Now,

x_1= \$24 , x_2=\$30 , x_3=$36

and

P(x_1)=\frac{1}{6},P(x_2)=\frac{1}{2}, P(x_3)=\frac{1}{3}

So,

E(X)= 24\times \frac{1}{6}+30\times\frac{1}{2}+36\times \frac{1}{3}\\=4+15+12\\=31

So, the expected value of a t-shirt = $31.

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3 years ago
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