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laiz [17]
3 years ago
15

During what phase of mitosis are you first able to see distinct chromosomes

Biology
2 answers:
Murrr4er [49]3 years ago
7 0

Answer: Prophase

Explanation:

Paraphin [41]3 years ago
6 0

Answer:

its actually the very first stage, the <em>prophase,</em> that each chromosome becomes more compressed and noticable, or as you said, distinct.

<u><em>~hope i helped ouo have a nice rest of ur day~</em></u>

<em>lots of love,</em>

<em>  lee</em>

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its B

Explanation:

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Which is a waxy, water-repelling outer covering of a plant?
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Read 2 more answers
Two linked genes, A and B, are separated by 18 cM. A man with genotype AB/ab marries a woman who is ab/ab. The man’s father was
kolbaska11 [484]

Answer:

a) 9%.  

b) 16.8%.

Explanation:

a).

We are provided with the information that Two linked genes, A and B, are separated by 18 cM (centiMorgan). i.e the recombinant frequency is 18%

Also , the man's genotype is AB/ab... This only result to one explanation, that The man will definitely produce 18% of recombinant gametes which entails

9% Ab & 9% aB

i.e 0.09 Ab & 0.09 aB

On the other-hand, The mother ab/ab have tendency to produce just one single type of gamete which is ab

∴

The probability that their first child will be Ab/ab will be

Pr ( Ab/ab) = (0.09) x (1)

= 0.09

= 9%.  

b).

If the father produces 18% of recombinant gametes which entails

9% Ab & 9% aB , this typically implies that the number of the non-recombinant gametes will be;

100%-18% = 82%  ( non-recombinant gametes)

i.e genotype AB/ab = 82%

AB =41%; ab = 41%

AB = 0.41 ; ab = 0.41

Now, the probability that their first two children will both be ab/ab:

Using Multiplication Rule to calculate the probability that their first two children (ab/ab); we have:

 (0.41)(1) ×(0.41)(1)

= 0.1681

= 16.8%.

5 0
4 years ago
What are the parts of a cell and is the nucleus part of the cytoplasm?!​
laila [671]

Answer:

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Explanation:

4 0
3 years ago
Humans are diploid organisms, and their gametes contain 23 chromosomes. Fill in the blank in each sentence using the terms. Each
USPshnik [31]

Answer:

2n, n, diploid

Explanation:

<em>When the somatic cells of human are in interphase, the ploidy level is denoted as </em><em>2n (diploid)</em><em>. The ploidy level of the human's gametes is denoted as </em><em>n (haploid)</em><em>. The 2n number of a human is </em><em>diploid</em><em>.</em>

Somatic cells are also known as vegetative cells and all somatic cells of humans have diploid number of chromosomes. At interphase, the number of chromosome remains diploid (2n) but the amount to DNA is doubled at the synthesis phase of the interphase.

Human gametes are formed through meiosis - the division of sex cells in the human body. Meiosis results in the halving of number of chromosomes of cells. Hence, all human gametes contain half the number (n = 23) of chromosome of vegetative cells.

Humans are diploid organisms with diploid (2n = 46) number of chromosomes in their vegetative cells.

5 0
3 years ago
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