To solve this problem you must apply the proccedure shown below. You have that:
1+cot^2θ=csc^2θ (You have that cos^2θ+sin^2θ=1)<span>
1+(cos^2</span>θ/sin^2θ)=csc^2θ
1+(1-sin^2θ/sin^2θ)csc^2θ
sin^2θ+1-sin^2θ=csc^2θ
1/sin^2=csc^2 (You have that 1/sin=csc)
Answer:
49/144
Step-by-step explanation:
(6,-9) bc downwards means (-) so -3-6=-9
a.) 1/2n 4=3−5/n b.) 1/2(n 4)=5/n−3 c.) 1/2(n 4)=3−5/n d.) 1/2n 4=5/n−3
Let's assume the number be n.
So, sum of number and four can be written as n+4.
Now one-half of n+4 will be
.
Quotient of five and the number can be written as
.
Now three less \frac{5}{n} can be written as \frac{5}{n} -3.
So, one-half the sum of a number and four is three less than the quotient of five and the number can be converted into equation as follows:

So, b is the correct choice.