Answer:
(From left to right) 2 5 8
Step-by-step explanation:
1. Find the gap (between the first and last terms) 11 - (-1) = 12
2. Divide by the number of times the linear term is added: 12/4=3
3. Use the common difference to find the missing values.
Answer:
??
Step-by-step explanation:
Answer: 10, 11, & 12
<u>Step-by-step explanation:</u>
Let x represent the age of the youngest child.
Their ages are consecutive so,
Youngest: x
Middle: x + 1
Oldest: x + 2
The age of the Youngest squared (x²) equals 8 times the Oldest [8(x + 2)] plus 4.
x² = 8(x + 2) + 4
x² = 8x + 16 + 4
x² = 8x + 20
x² - 8x - 20 = 0
(x - 10)(x + 2) = 0
x - 10 = 0 or x + 2 = 0
x = 10 or x = -2
Since age cannot be negative, x = -2 is not valid
So, the Youngest (x) is 10
the Middle (x + 1) is 11
and the Oldest (x + 2) is 12
If you would like to solve the equation - 2/5 * x + 6 = 8, you can do this using the following steps:
- 2/5 * x + 6 = 8
- 2/5 * x = 8 - 6
- 2/5 * x = 2 /*(-5/2)
x = 2 * (- 5/2)
x = - 5
The correct result would be -5.
The answer to the question is it would add twenty seven every two times it goes up
