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klio [65]
3 years ago
6

A standard basketball court is 50 feet by 94 feet what is the total surface area in square feet?

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0
The answer is 4,700 square feet
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Need help fast right now. Find the surface area of each solid. Round to the nearest tenth of necessary.
Mice21 [21]

Answer:

5)surface =2(lb*bh*hl)

=2(12*4+4*4+4*12)

=2(48+16+48)

=2(96+16)

=2*112

=224inc^2

6)surfacearea=2*pi*r(r+h)

=2*3.14*2(2+1)

=6.28*2*3

=6.28*6

=37.68m^2

7 0
3 years ago
Need help ASAP<br> find the mean,median, range and IQR<br> brainliest
N76 [4]
The mean= 5.5

The median= 6

The range= 10

The IQR= 5

I really hope this helps:)
4 0
3 years ago
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Please help asap!<br><br> Use the difference quotient to find the derivative of f(x)= 4/x at x=3.
saveliy_v [14]
F (x)= 4/x

F(3)= 4/3

4/3 I think
4 0
3 years ago
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Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units. What would be the perimeters of the
Dmitriy789 [7]

Answer:

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

Step-by-step explanation:

Given - Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units.

To find -  What would be the perimeters of the other rectangles Orbet could make using only these 24 tiles? How do the areas of the rectangles compare?

Proof -

We know that

Are of Rectangle = Length × Breadth

And Perimeter of Rectangle = 2 (Length + Breadth )

Now,

Given that,

Orbet used 24 square tiles

And perimeter of the rectangle made = 20

So,

Possible Length of rectangle = 6

Possible breadth of Rectangle = 4

Or Vice-versa.

Total number of Rectangles possible = 4

Possibilities are -  1 × 24, 2 × 12, 3 × 8, 4 × 6

Case I :

Length of rectangle = 1

Breadth of rectangle = 24

∴ Perimeter of rectangle = 2(1 + 24) = 2(25) = 50 units

Area of rectangle = 1 × 24 = 24 unit²

Case II :

Length of rectangle = 2

Breadth of rectangle = 12

∴ Perimeter of rectangle = 2(2 + 12) = 2(14) = 28 units

Area of rectangle = 2 × 12 = 24 unit²

Case III :

Length of rectangle = 3

Breadth of rectangle = 8

∴ Perimeter of rectangle = 2(3 + 8) = 2(11) = 22 units

Area of rectangle = 3 × 8 = 24 unit²

Case IV :

Length of rectangle = 4

Breadth of rectangle = 6

∴ Perimeter of rectangle = 2(4 + 6) = 2(10) = 20 units

Area of rectangle = 4 × 6 = 24 unit²

∴ we get

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

5 0
3 years ago
Popular magazines rank colleges and universities on their ""academic quality"" in serving undergraduate students. Describe two c
Reika [66]

Answer:

Quantitative: i) The number of students in the school vis - a - vis the number of classes in the school. In order words, simply number of students per class

ii) The rate of graduation of students.

Categorical:i) Courses being taken by students

ii) Region of country of students.

Step-by-step explanation:

To answer this question effectively, it's important for us to know that a quantitative variable usually has numerical values, and also have units of measure as well while categorical variables simply places each student into a specific category.

Now, the two quantitative variables we will consider are;

i) The number of students in the school vis - a - vis the number of classes in the school. In order words, number of students per class

ii) The rate of graduation of students.

Also, the two categorical variables we will consider are;

i) Courses being taken by students

ii) Region of country of students

5 0
3 years ago
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