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mart [117]
3 years ago
13

Point M is the midpoint between points A and B. If A(−5, 4) and B(−1, −8) find the location of M. M is located at the point . AS

AP PLEASEEE
Mathematics
1 answer:
Elanso [62]3 years ago
5 0

Answer:

i think it is -3,-2

Step-by-step explanation:

i dont have one

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The function fx) is graphed below.
Shtirlitz [24]

Answer:

D. 2

Step-by-step explanation:

following the graph you can see that -2 on the x line comes across to 2 in y line

3 0
3 years ago
Question 10 of 21
PSYCHO15rus [73]

<u>ANSWER</u>

A. (4,12)

<u>EXPLANATION</u>

The equations are:

10x +2y = 64...(1)

and

3x - 4y = -36...(2)

To eliminate a variable we make the coefficients of that variable the same in both equations.

It is easier to eliminate x.

We multiply the first equation by 2 to get:

20x + 4y = 128...(3)

We add equations (2) and (3).

3x + 20x + 4y - 4y =  - 36 + 128

23x = 92

Divide both sides by 23

\frac{23x}{23}  =  \frac{92}{23}

x = 4

Put x=4 into equation (1).

10(4)+2y = 64

40+2y = 64

2y = 64 - 40

2y = 24

\frac{2y}{2}  =  \frac{24}{2}

y = 12

The solution is (4,12)

6 0
3 years ago
Zoey bought a plant and planted it in a pot near a window in her house. Let H
lys-0071 [83]

Answer:

9

Step-by-step explanation:

7 0
3 years ago
Can someone please help me?
den301095 [7]
Idk try Socratic it’s low key
3 0
3 years ago
Read 2 more answers
If f(x)=sinx 2x 1 and g is the inverse function of f
Bingel [31]

The value of the derivative of the function g(x) at x = 1 will be 1/3. Then the correct option is A.

<h3>What is an inverse function?</h3>

A function that may convert into another function is known as an inverse function or anti-function.

If the function is f(x) = sinx + 2x + 1.

Then the derivative of an inverse function g(x) of a function f(x) at a given value (a) will be

\rm g'(a) = \dfrac{1}{f'(g(a))}

The derivative of f(x) will be

f'(x) = cos x + 2

Then the given value of a will be

a = 1

g(x) = f⁻¹(x)

put x = 0, then we have

f(0) = sin 0 + 2(0) + 1

f(0) = 1

Put x = 1, in the function f⁻¹(x). Then we have

f⁻¹(1) = 0

and

g(1) = 0

Then put a = 1, then we have

\rm g'(a) = \dfrac{1}{f'(g(a))}\\\\g'(1) = \dfrac{1}{f'(g(1))}\\\\g'(1) = \dfrac{1}{f'(0)}\\\\g'(1) = \dfrac{1}{\cos 0 + 2}\\\\g'(1) = \dfrac{1}{1+2}= \dfrac{1}{3}

More about the inverse function link is given below.

brainly.com/question/2541698

#SPJ4

8 0
2 years ago
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