Answer:
B. 9 feet
Step-by-step explanation:
area = side^2
side^2 = 84
side = sqrt(84)
side = 9.2 ft
Each side of a wall measures 9.2 ft.
Answer:
the answer above me don't click it that's kinda sus sooo
Step-by-step explanation:
The box in the shape of a rectangular prism it measures 15 in. long, 11 in. wide, and 24 in. tall A so in B in.2 © 789 in.2 1,578 in.2
1 subscription = $21
28 subscriptions = x
You know 1 subscription is $21
You want to find out how much 28 subscriptions are
Multiply 28 (subscriptions) by 21 ($ per subscription)
28 x 21 = 588
28 subscriptions cost $588
If you would like the formula to find out how many subscriptions cost hat amount of money,
21x = y
x is how many subscriptions you want, while y is the total cost of the money
<h3>Answer: The month of April</h3>
More accurately: The correct time will be shown on April 4th if it is a leapyear, or April 5th if it is a non-leapyear. It takes 60 days for the clock to realign, which is the same as saying "the clock loses 24 hours every 60 days".
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Explanation:
The following statements shown below are all equivalent to one another.
- Clock loses 1 second every 1 minute (original statement)
- Clock loses 60 seconds every 60 minutes (multiply both parts of previous statement by 60)
- Clock loses 1 minute every 1 hour (time conversion)
- Clock loses 60 minutes every 60 hours (multiply both parts of previous statement by 60)
- Clock loses 1 hour every 2.5 days (time conversion)
- Clock loses 24 hours every 60 days (multiply both parts of previous statement by 24)
Use a Day-Of-Year calendar to quickly jump ahead 60 days into the future from Feb 4th (note how Feb 4th is day 35; add 60 to this to get to the proper date in the future). On a leapyear (such as this year 2020), you should land on April 4th. On a non-leapyear, you should land on April 5th. The extra day is because we lost Feb 29th.
The actual day in April does not matter as all we care about is the month itself only. Though it's still handy to know the most accurate length of time in which the clock realigns itself.
