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irga5000 [103]
4 years ago
7

What is a integer and a rational number? (That was 2 questions)

Mathematics
2 answers:
liubo4ka [24]4 years ago
4 0
An integer is basically a whole number and any other number that is not a fraction but a rational number is any number that can be expressed as the quotient or fraction. EVERY INTEGER IS A RATIONAL NUMBER!
sp2606 [1]4 years ago
3 0
An integer is a number that can be either positive or negative. Examples are -5 and 5. Both numbers are integers because they are both negative or positive. Real numbers are everything except for repeating decimals. Pi for example is an irrational number
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Write an algebraic expression for eight less than four times a number
natta225 [31]

4x - 8, 4x just means four of x, and eight less means to subtract 8.

4 0
4 years ago
If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?
Oduvanchick [21]
Remember that (g-f)(x) is g(x)-f(x). We know form our problem that f(x)=4-x^2 and g(x)=6x, so:
(g-f)(x)=g(x)-f(x)
(g-f)(x)=6x-(4-x^2)
(g-f)(x)=6x-4+x^2

Now, to find (g-f)(3), we just need to evaluate (g-f)(x) at 3. In other words, we are going to replace x with 3:
(g-f)(x)=6x-4+x^2
(g-f)(x)=6(3)-4+(3)^2

We can conclude that the correct answer is <span>C.6(3) – 4 + 3^2 </span>

5 0
3 years ago
What is the perimeter of a rectangle with a length of 11.5 yd and a width of 5 yd?
Tems11 [23]
Answer = B - 33yd

Because the perimeter is all the sides added up so you do length + length + width + width = 11.5 + 11.5 + 5 + 5 = 33
7 0
4 years ago
Help with this question please
Veronika [31]

Answer:

I don't normally really really really really really really really really

3 0
3 years ago
The owner of a construction company would like to know if his current work teams can build room additions quicker than the time
frez [133]

Answer:

The claim that the current work teams can build room additions quicker than the time allotted for by the contract has strong statistical evidence.

Step-by-step explanation:

We have to test the hypothesis to prove the claim that the work team can build room additions quicker than the time allotted for by the contract.

The null hypothesis is that the real time used is equal to the contract time. The alternative hypothesis is that the real time is less thant the allotted for by the contract.

H_0: \mu=0\\\\H_1: \mu

The significance level, as a storng evidence is needed, is α=0.01.

The estimated standard deviation is:

s_M=\frac{s}{\sqrt{n}}=\frac{0.2}{\sqrt{16}} =0.2/4=0.05

As the standard deviation is estimated, we use the t-statistic with (n-1)=15 degrees of freedom.

For a significance level of 0.01, right-tailed test, the critical value of t is t=2.603.

Then, we calculate the t-value for this sample:

t=\frac{x-\mu}{s_M} =\frac{-0.32-0}{0.05}= -6.4

As the t-statistic lies in the rejection region, the null hypothesis is rejected. The claim that the current work teams can build room additions quicker than the time allotted for by the contract has strong statistical evidence.

8 0
4 years ago
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