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shtirl [24]
4 years ago
12

On an average day, a horse might drink 50 L a sheep might drink 4 l and a chicken might drink 200 mL how much water would a farm

need with 4 horses 8 sheep and 16 chickens need for a day
Mathematics
1 answer:
Elan Coil [88]4 years ago
4 0

Answer:

The farm would need 235.2 liters daily for 4 horses, 8 sheep and 16 chickens.

Step-by-step explanation:

The daily consumption of water in the farm must be:

x = (4\,horses)\times \left(50\,\frac{L}{horse} \right) + (8\,sheep)\times \left(4\,\frac{L}{sheep} \right) + (16\,chickens)\times \left(0.2\,\frac{L}{chicken} \right)

x = 235.2\,L

The farm would need 235.2 liters daily for 4 horses, 8 sheep and 16 chickens.

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(2/7)m - (1/7) = 3/14
2m/7 =(3/14) + (1/7)
2m/7 = (3/14) + 2(1/7)
here we are multiplying 2 with 1/7 to make the denominator same for addition.
2m/7 = (3/14) +(2/14)
2m/7 = (3 + 2)/14
2m/7 = 5/14
2m = (5 *7)/14
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m = 5/4
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Ansswer:

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