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zubka84 [21]
3 years ago
12

This should be easy but plz explain in the best way thank u

Mathematics
1 answer:
pentagon [3]3 years ago
3 0

Answer:

The answer is 1.

Step-by-step explanation:

9^15 = 205891132094649

205891132094649(1/205891132094649 )

Cancel the common factor of "205891132094649 "

You are left with 1.

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yawa3891 [41]
500=4πr^2. first divide 500 from four which will equal 125, then divide 125 with π and it will equal 39.788 . finally √39.788. the answer will be r=6.3 or 6
8 0
3 years ago
15=x/4 - 3 how do i solve
zhuklara [117]

Answer: the answer is x=72

Step-by-step explanation:

Step 1: simplify both sides we know 15=x/4 -3 (the x holds a invisible 1)

the equation should look something Like: 15=1/4x-3 then FLIP the equation such as:

1/4x-3=15 then add 3 on both sides so 15+3=18

step 2: our equation is now 1/4x=18  (we see 4 is being divided the opposite of division is multiply) therefor multiply the 18 with 4

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2 years ago
Roy drives a sedan that gets mileage of 30 miles per gallon. If fuel consumption is represented by g and mileage by m, which fun
tankabanditka [31]
I don’t know, I just need to answer 2 questions before it gives me answers
7 0
3 years ago
Find the sum of the odd integers between 24 and 50
morpeh [17]

Answer:

  481

Step-by-step explanation:

There are several ways you can get there.

1. There are only 13 numbers, so you can write them down and add them up.

  25 + 27 + 29 + ... + 47 + 49 = 481

__

2. You can use the formula for the sum of an arithmetic sequence. This one has a starting value of 25, an ending value of 49, and 13 terms.

  Sum = ((start) + (end))/2 × (number of terms) = (25 +49)/2×13 = 481

__

3. You can use a formula for the terms of the series and evaluate the sum.

  an = 25 +2(n -1) = 2n +23

\sum\limits_{n=1}^{13}{(2n+23)}=2\sum\limits_{n=1}^{13}(n)+\sum\limits_{n=1}^{13}{(23)}=2\dfrac{13\cdot 14}{2}+13\cdot 23=481

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3 years ago
Janet set off on a bicycle trip at 7:30 a.m.
UNO [17]

the answer is 10:20.

Hint for the future: be sure to write in the full problem. I only knew the answer because I had to do it myself, but people need more context if they are going to help you.

3 0
4 years ago
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