All categories

4 years ago

What is 16/63 in simplest form

Mathematics

2 answers:

Musya8 [376]4 years ago

8 0

Divide the numbers by what they equal too

Monica [59]4 years ago

7 0

As a decimal, 0.25396825396. As a fraction, it is already simplified.

You might be interested in

2x - 11| + 6 = -5 What is it?

mezya [45]

Answer:

No solution

Step-by-step explanation:

The answer is no solution because an absolute value cannot equal or be a number.

3 0

3 years ago

How much is 3 liters in 50 bottles

katrin2010 [14]

Answer : 0.06 liters per bottle

Step - by - step explanation :

3 liters divided by 50 bottles = 0.06 liters per bottle

[ Sorry if this wasn't what you meant when you asked the question ]

Happy holidays ! :3

6 0

3 years ago

Simplify: -4(w + 1) + 5w A. -9w + 4 B. -9w – 4 C. w + 4 D. w – 4

kenny6666 [7]

Answer:

Step-by-step explanation:

D. W - 4

6 0

3 years ago

The Captain has probability 2/3 of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with

finlep [7]

Answer:

What we have to do bro

Step-by-step explanation:

please mark me as brainlest

8 0

3 years ago

Read 2 more answers

Sin(A+B) sin(A-B) /sin^A Cos^B=1-cot^A Tan^B

telo118 [61]

In order to prove

$\dfrac{\sin(x+y)\sin(x-y)}{\sin^2(x)\cos^2(x)}=1-\cot^2(x)\tan^2(y)$

Let's write both sides in terms of $\sin(x),\ \sin^2(x),\ \cos(x),\ \cos^2(x)$ only.

Let's start with the left hand side: we can use the formula for sum and subtraction of the sine to write

$\sin(x+y)=\cos(y)\sin(x)+\cos(x)\sin(y)$

and

$\sin(x-y)=\cos(y)\sin(x)-\cos(x)\sin(y)$

So, their multiplication is

$\sin(x+y)\sin(x-y)=(\cos(y)\sin(x))^2-(\cos(x)\sin(y))^2\\=\cos^2(y)\sin^2(x)-\cos^2(x)\sin^2(y)$

So, the left hand side simplifies to

$\dfrac{\cos^2(y)\sin^2(x)-\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

Now, on with the right hand side. We have

$1-\cot^2(x)\tan^2(y)=1-\dfrac{\cos^2(x)}{\sin^2(x)}\cdot\dfrac{\sin^2(y)}{\cos^2(y)} = 1-\dfrac{\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

Now simply make this expression one fraction:

$1-\dfrac{\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}=\dfrac{\sin^2(x)\cos^2(y)-\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

And as you can see, the two sides are equal.

6 0

4 years ago