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Gnom [1K]
3 years ago
13

1. Given the function f(x) = -4x + 5 , find f(2). y = 3 Y=-3 y = 13 y = -13

Mathematics
2 answers:
Sonja [21]3 years ago
4 0

Answer:

<h2>y = - 3</h2>

Step-by-step explanation:

f(x) = -4x + 5

To find f(2) , substitute the value of x that's 2 into f(x). That is for every x in f(x) replace it with 2

That's

f(2) = - 4(2) + 5 = - 8 + 5

We have the final answer as

<h3>y = - 3</h3>

Hope this helps you

IrinaVladis [17]3 years ago
4 0

Answer:

B

Step-by-step explanation:

f(x) = -4x + 5

f(2) = -4(2) + 5

f(2) = -8 + 5

f(2) = -3

Best of Luck!

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A store has a coupon for $10 off and a discount of 20%. Write a function for the coupon. Use x for the original price and C for
Ludmilka [50]
<h2>Explanation:</h2><h2></h2>

We know some facts:

  • x for the original price.
  • The store has a coupon for $10 off and a discount of 20%
  • C for the price after the coupon is applied.

So from the statement 2, you can realize there are two types of discounts:

  1. The discount offered by the coupon
  2. The discount offered by 20%

Since we need to write a function just for the coupon, then we don't include the discount offered as percentage, then we subtract the coupon from the original price:

\boxed{C=x-10}

8 0
3 years ago
A trapezoid has a height of 6 ft and a total area of 30 ft^. What are the possible lengths of the bases. Explain your reasoning.
gtnhenbr [62]
The area of a trapezoid = (a + b)/2 x h
Where a and b are the lengths of the parallel sides and h is the perpendicular distance between them.
When (a + b)/2 x 6 = 30
then (a + b)/2 = 5
a + b = 10

Possible values for (a,b) are (4,6) (3,7) (2,8) (1,9) assuming a < b but (7,3) is also valid.
Any positive real value is possible so (4.8, 5.2) and (0.3, 9.7) are valid

In general {a,b both real: 0
3 0
3 years ago
Simone has 5 employees in her flower shop. each employee works 6 4/15 hours per day.how many hours in total do the 5 employees w
STALIN [3.7K]
5/1 x 6 4/15

5/1 x 94/15

Answer: 94/3 or 31 1/3
3 0
3 years ago
A cone with volume 5000 m³ is dilated by a scale factor of 15. What is the volume of the resulting cone? Enter your answer in th
Rasek [7]

Answer:

40\ m^{3}

Step-by-step explanation:

we know that

If two figures are similar then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z-----> scale factor

x-----> the volume of the dilated cone

y-----> the volume of the original cone

z^{3}=\frac{x}{y}

In this problem we have

z=1/5

y=5,000\ m^{3}

substitute and solve for x

(1/5)^{3}=\frac{x}{5,000}

(1/125)=\frac{x}{5,000}

x=5,000/125=40\ m^{3}

5 0
3 years ago
Read 2 more answers
Identify the class​ width, class​ midpoints, and class boundaries for the given frequency distribution.
Crank

Answer:

a. Class width=4

b.

Class midpoints

46.5

50.5

54.5

58.5

62.5

66.5

70.5

c.

Class boundaries

44.5-48.5

48.5-52.5

52.5-56.5

57.5-60.5

60.5-64.5

64.5-68.5

68.5-72.5

Step-by-step explanation:

There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,

Class

Interval frequency

45-48 1

49-52 3

53-56 5

57-60 11

61-64 7

65-68 7

69-72 1

a)

Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.

Class width=49-45=4

b)

The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

M=\frac{lower class limit+upper class limit}{2}

Class

Interval Midpoints

45-48 \frac{45+48}{2}=46.5

49-52 \frac{49+52}{2}=50.5

53-56 \frac{53+56}{2}=54.5

57-60 \frac{57+60}{2}=58.5

61-64 \frac{61+64}{2}=62.5

65-68 \frac{65+68}{2}=66.5

69-72 \frac{69+72}{2}=70.5

c)

Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.

Class

Interval Class boundary

45-48 44.5-48.5

49-52 48.5-52.5

53-56 52.5-56.5

57-60 56.5-60.5

61-64 60.5-64.5

65-68 64.5-68.5

69-72 68.5-72.5

7 0
3 years ago
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