Answer:
D
Step-by-step explanation:
Sample space = {H1,H2, H3, H4, H5, H6 , T1, T2, T3, T4, T5, T6}
So, (H, 6) is an element in the sample space
Answer: A reflection (Across the y-axis)
Step-by-step explanation:
Transformation possiblitites:
Translation: After plotting the points you gave I came to the conclusion that a translation could not be the right transformation due to the fact that the point would move away the same units on a graph as the original point.
Rotation: The new point doesn't seem when graphed to have rotated, as it remained across from the orignial point on the graph.
Dilation: The new point if dilated wouldn't be in close proximity with the original point.
So in matt's equation, he made a mistake in the a transision from line 2 to line 3
in line 2: -4(-2)2
in line 3: -4(4)
the mistake is that -2 times 2 is not equal +4 it is equal to -4
also from lines 5 to 6 he made a mistake in order of opperations (mulit division then addition and subtract)
line 5: -10+30/5
line 6: 20/5
so he first subtracted 10 then divided, he should have divided then subtracted
so the equation should have equaled
Karen used the correct (-) times (+) property and the order of operations
so Karen is correct and Matt is wrong.
Answer:
A. 2y = 22
Step-by-step explanation:
You are basically combining like terms. Look at the equation and subtract from top to bottom.
You will subtract 5x and 5x, 4y and 2y, and 25 and 3.
Now you have 0 + 2y = 22.
Removing the 0 (because it is worth nothing), you will be left with 2y = 22 which corresponds to A.
Answer:
A function is a relation that for each input, there is only one output.
Here are mappings of functions. The domain is the input or the x-value, and the range is the output, or the y-value.
Each x-value is related to only one y-value.
Athough the inputs equal to -1 and 1 have the same output, this relation is still a function because each input has just one output.
This mapping is not a function. The input for -2 has more than one output.
I hope that helps. I don't know if it is right or wrong, but good luck :)
