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2 years ago

If ED = x + 4 and DB = 3x - 8, find ED, DB, and EB

Mathematics

2 answers:

Flura [38]2 years ago

8 0

Answer:

$20 = EB$

$10 = DB$

$10 = ED$

Step-by-step explanation:

By definition, according to this cross-section model, point $D$ is the segment bisector of all segments, according to which segments they are in congruence with. Anyway, here is how it is done:

3x - 8 = x + 4

-3x - 3x

_____________

−8 = −2x + 4

-4 - 4

_____________

−12 = −2x

____ ____

−2 −2

$6 = x$ [Plug this back into all expressions above to get the measurements of $20 = EB$ , $10 = DB$ , $10 = ED$ ]

* Since point $D$ the segment bisector, you set the given equations equal to each other, then in the end, plug the x-value back into all expressions to get the length of $EB$ .

I am joyous to assist you anytime.

Tom [10]2 years ago

5 0

Answer:

Part 1) $ED=10\ units$

Part 2) $DB=10\ units$

Part 3) $EB=20\ units$

Step-by-step explanation:

we know that

EB=ED+DB

ED=DB -----> given problem

Substitute the given values and solve for x

$x+4=3x-8$

$3x-x=4+8$

$2x=12$

$x=6$

Find the value of ED

$ED=x+4$

substitute the value of x

$ED=6+4=10\ units$

Find the value of DB

Remember that

ED=DB

therefore

$DB=10\ units$

Find the value of EB

EB=ED+DB

$EB=10+10=20\ units$

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vekshin1

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3 years ago

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Alex Ar [27]

Answer:

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Step-by-step explanation:

$a_1=3,\ a_2=3+5=8,\ a_3=8+5=13,\ a_4=13+5=18\ \implies\ d=5\\\\a_n=a_1+(n-1)d\\\\a_n=3+(n-1)(5)\\\\a_n=3+5n-5\\\\a_n=5n-2\\\\ a_n=78\quad\implies\quad n=\,??\\\\78=5n-2\\\\78+2=5n\\\\5n=80\\\\n=16$

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3 years ago

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3 0

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