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Elden [556K]
4 years ago
11

Evaluate 3w+(8-v)t if w=4, v=5, and t=2 Please help!!!!

Mathematics
2 answers:
Masja [62]4 years ago
5 0
The answer is 18.
3(4)+(8-5)2
=3(4)+(3)2
=12+6
=18
Bezzdna [24]4 years ago
4 0

well, start off by replacing the variables (letters) with the matching numbers 3w + (8-v)t = 3(4) + (8-5)2, agreed?
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Answer:

Plot f(x)=x^4+x^3-8x^2-12x

Step-by-step explanation:

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Calculus 2 Master needed, show steps with partial fraction decomposition <img src="https://tex.z-dn.net/?f=%5Cint%283x%5E2-26x%2
Vladimir79 [104]

Answer:

-ln|x−5| + 2 ln(x²+4) + 3 tan⁻¹(x/2) + C

Step-by-step explanation:

The fraction will be split into a sum of two other fractions.

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The second fraction will have a denominator of x² + 4.  The numerator will be Bx + C.

\frac{3x^{2}-26x+26}{(x-5)(x^{2}+4)}=\frac{A}{x-5} +\frac{Bx+C}{x^{2}+4}

Combine the two fractions back into one using the common denominator.

\frac{A}{x-5} +\frac{Bx+C}{x^{2}+4}=\frac{A(x^{2}+4)+(Bx+C)(x-5)}{(x-5)(x^{2}+4)}

This numerator will equal the original numerator.

A(x^{2}+4)+(Bx+C)(x-5)=3x^{2}-26x+26\\Ax^{2}+4A+Bx^{2}-5Bx+Cx-5C=3x^{2}-26x+26\\(A+B)x^{2}+(C-5B)x+(4A-5C)=3x^{2}-26x+26

Match the coefficients.

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Solve the system of equations.

A=-1\\B=4\\C=-6

So we can rewrite the integral as:

\int {(\frac{-1}{x-5}+\frac{4x-6}{x^{2}+4}) } \, dx

Solving:

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-\int {\frac{1}{x-5}\, dx + 2\int {\frac{2x}{x^{2}+4}} \, dx - 6\int {\frac{1}{x^{2}+4} } \, dx

-ln|x-5| + 2ln(x^{2}+4) - 6(\frac{1}{2} tan^{-1}(\frac{x}{2} )) + C

-ln|x-5| + 2ln(x^{2}+4) - 3 tan^{-1}(\frac{x}{2} ) + C

5 0
3 years ago
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Answer:

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