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Dima020 [189]
3 years ago
10

In a year, almost a billion people on the planet didn't have access to clean drinking water. If there were 5.2 *10^9 people in t

he world, then approximately what percentage of them lived without clean water
Mathematics
2 answers:
xz_007 [3.2K]3 years ago
8 0
Approximately 19.2% of the world would not have clean drinking water.
ioda3 years ago
8 0
5.2 × 10⁹ in standard notation is <span>5,200,000,000.
If 1 billion people (1,000,000,000) didn't have access to clean drinking water, then that means as a percentage, 19.2% of the world population didn't have access to clean drinking water.

You can work this out by doing </span>( \frac{1000000000}{5200000000}) × 100 (which is 19.2<span>307...%) and then round to the nearest tenth (which is 19.2%). </span>
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Erika is working on solving the exponential equation 50^x = 17; The solution is x = 0.7242.

<h3>What is logarithm?</h3>

When you raise a number with an exponent, there comes a result.

Let's say you get

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Then, you can write 'b' in terms of 'a' and 'c' using a logarithm as follows

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Erika is working on solving the exponential equation 50^x = 17;

however, she is not quite sure where to start.

The equation is

50^x = 17\\

By taking the log both sides

log_a b = x\\\\a_x = b

By using the base formula

log_0 y = \dfrac{logy}{log b}

So, log_{50} 17= x\\\\

x = \dfrac{log17}{log 50}

x = 0.7242

Learn more about logarithm here:

brainly.com/question/20835449

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