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EleoNora [17]
3 years ago
10

Is the sequence Arithmetic or Geometric? -2, 4.-8, 16, ...

Mathematics
1 answer:
Sonbull [250]3 years ago
6 0

Answer:

This is an geometric sequence because the common ratio is -2.

Step-by-step explanation:

-2*-2=4

4*-2=-8

-8*-2=16

So, as we are seeing that the common ratio is -2, so this is an geometric sequence.

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Which scatter plot would have a trend line with a negative y-intercept
bazaltina [42]

Answer:

Only Graph D

Step-by-step explanation:

A trend line indicates the general course (or average course) of the points on the graph. In Graph C, the general trend seems to intercept at a positive y-value. In Graph D, the trend will continue past the X-axis and intercept at the negative Y-axis.

8 0
4 years ago
solve the proportion. the quantity 13 minus b end of quantity divided by 6 equals the quantity 2 minus 0.5 multiplied by b end o
tatyana61 [14]
\frac{13-b}{6}= \frac{2-0.5b}{4} \\ 4(13-b)=6(2-0.5b) \\ 52-4b=12-3b \\ b=40
5 0
3 years ago
Does anyone know this?
madreJ [45]
33/65

sine = “opposite”/hypotenuse

Unfortunately, I currently can’t draw a diagram, but if you draw a right triangle with corners labeled I, H, and G, the side opposite to angle G is 33. The hypotenuse, aka the longest side of the triangle, is 65.

Hence, the ratio would be 33/65.
8 0
3 years ago
√7, 2, √8/2 <br>order the number from least to greatest
REY [17]
To get a feel for where those two radicals fall on the number line, take a look at the perfect square roots they fall between. Both sqrt(7) and sqrt(8) fall between the perfect square roots sqrt(4) and sqrt(9); since sqrt(4) = 2 and sqrt(9) = 3, we know that sqrt(7) and sqrt(8) are somewhere in between 2 and 3. This means we know that sqrt(7) > 2. What about sqrt(8)/2 though? Well, sqrt(4)/2 = 2/2 = 1, and sqrt(9)/2 = 3/2 = 1 1/2, so sqrt(8)/2 has to be between 1 and 1 1/2, both of which are less than 2. Putting those all in order:

sqrt(8)/2, 2, sqrt(7)
7 0
3 years ago
A long spring is attached to a wall at one end. A pulse is sent down the spring. When the pulse reaches the wall it bounces back
Vika [28.1K]

It is given that at the moment the first pulse reaches the wall, a second pulse is sent down the spring. Now, when the two pulses meet they will be subject to the principle of superposition and as one is upside down (the reflected pulse) and the other is up (the second pulse), there will be a nullifying effect and the spring will appear straight for that split moment. Thus we can say that there will be a destructive interference where one pulse will destroy the other or in other words nullify the other's existence. After that moment the pulses will move towards their respective ends as if nothing happened.

Hence, Option B is the correct option.

3 0
3 years ago
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