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3 years ago

3⁄2 c + 23 = 38 can you help me find out what c is pretty please

Mathematics

1 answer:

kolbaska11 [484]3 years ago

6 0

Answer:

C=10

Step-by-step explanation:

To solve this problem, first, you have to isolate it on one side of the equation. Remember, isolate c on one side of the equation.

3/2c+23-23=38-23 (subtract 23 from both sides.)

38-23 (solve.)

38-23=15

3/2c=15

2*3/2c=15*2 (multiply 2 from both sides.)

15*2 (solve.)

15*2=30

3c=30

3c/3=30/3 (divide by 3 from both sides.)

30/3 (solve.)

30/3=10

c=10

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If mJI = (3x+2)°, mHLK = (15x-36)°, and m∠HML = (8x-1)°, find mHLK

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The value of mHLK will be "(204)°".

Step-by-step explanation:

The given values are:

mJI = (3x+2)°

mHLK = (15x-36)°

and,

m∠HML = (8x-1)°

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Now,

By using chord-chord formula of angle, we get

$mHMK=\frac{1}{2}(mJL+mHLK)$

On putting the values in the above formula, we get

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On applying cross-multiplication, we get

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⇒ $16x-2=18x-34$

On subtracting "18x" from both sides, we get

⇒ $16x-2-18x=18x-34-18x$

⇒ $-2x-2=-34$

On adding "2" both sides, we get

⇒ $-2x=-34+2$

⇒ $-2x=-32$

⇒ $x=\frac{32}{2}$

⇒ $x=16$

On putting the value of "x" in mHLK = (15x-36)°, we get

⇒ (15x-36)° = (15×16-36)°

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⇒ = (204)°

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