20,25 and 35,50 and 10,15. Each pair would have a GCF of 5.
from the diagram, we can see that the height or line perpendicular to the parallel sides is 8.5.
likewise we can see that the parallel sides or "bases" are 24.3 and 9.7, so
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=8.5\\ a=24.3\\ b=9.7 \end{cases}\implies \begin{array}{llll} A=\cfrac{8.5(24.3+9.7)}{2}\\\\ A=\cfrac{8.5(34)}{2}\implies A=144.5~in^2 \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%3D8.5%5C%5C%20a%3D24.3%5C%5C%20b%3D9.7%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B8.5%2824.3%2B9.7%29%7D%7B2%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B8.5%2834%29%7D%7B2%7D%5Cimplies%20A%3D144.5~in%5E2%20%5Cend%7Barray%7D)
Answer:
Step-by-step explanation:
all we have to do is plug in 2 for x into the equation:
-8(2) + 5 -2(2) -4 + 5(2)
-16 + 5 -4 -4 + 10
-11 -8 + 10
-19 + 10
the answer is
-9
to simplify the equation we’ll combine like terms
-8x + 5 -2x -4 + 5x
-10x + 1 + 5x
-5x + 1
now we’ll plug in 2 for x
-5(2) + 1
-10 + 1
the answer is still
-9
When the radius is doubled, the volume of a cylinder quadruple
Answer:
Therefore the required ways are =190
Step-by-step explanation:
Combination: Combination is the number of selection of items from a collection of items where the order of selection does not matter.
Total number of smartphones =22
Defective phone = 2
Non defective phone = (22-2) =20
The control inspector randomly test 4 smartphones of which 2 are defective.
Non defective phone = 2
The ways to select 2 non defective phone is
![^{20}C_2=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!}=\frac{19\times 20}{2} =190](https://tex.z-dn.net/?f=%5E%7B20%7DC_2%3D%5Cfrac%7B20%21%7D%7B2%21%2820-2%29%21%7D%20%3D%5Cfrac%7B20%21%7D%7B2%2118%21%7D%3D%5Cfrac%7B19%5Ctimes%2020%7D%7B2%7D%20%3D190)
The ways to select 2 defective phone is= ![^2C_2=1](https://tex.z-dn.net/?f=%5E2C_2%3D1)
Therefore the required ways are = (190×1) =190