Question

What is an equation of the line that passes through the points (-6, -7) and (6, 3)?

Answer 1

Answer:

y+7=5/6(x+6)

Step-by-step explanation:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)

m=(3-(-7))/(6-(-6))

m=(3+7)/(6+6)

m=10/12

m=5/6

y-(-7)=5/6(x-(-6))

y+7=5/6(x+6)