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Answer:
dy/dx = 2x+1/x(x+1)
Step-by-step explanation:
y = In x(x+1)
Let u = x(x+1) = x^2 + x
du/dx = 2x + 1
y = In u
dy/du = 1/u
dy/dx = dy/du × du/dx = 1/u × 2x+1 = 2x+1/u = 2x+1/x(x+1)
I do not answer I mean College and I passed it
