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Neporo4naja [7]
3 years ago
12

Which property of inequalities states that if x ≤ 5 and 5 ≤ y , then x ≤ y?

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

Transitive property of inequality.

Step-by-step explanation:

Transitive property of inequality states that if

a\leq b\text{ and }b\leq c\text{ then }a\leq c

a\geq b\text{ and }b\geq c\text{ then }a\geq c

Now, the given conditions are x ≤ 5 and 5 ≤ y, then x ≤ y

It is same as the transitive property stated above. When we compare, we get

a = x, b = 5, c = y

Therefore, the given inequalities is transitive property of inequality.

Veseljchak [2.6K]3 years ago
7 0
<h2>Hello!</h2>

The answer is: The transitive property.

<h2>Why?</h2>

Inequalities express the relative size between two values/numbers.

The transitive property of inequalities states that there's a way to relate two or more inequalities when they have at least a common value, and we can use it to create a relationship with a third or more values/variables.

For your statement, we have

A common value which is 5

Two inequalities expressing a relative size between <u>two variables</u> and a common value which is 5:

x\leq 5\\5\leq y

So, the inequalities are telling us that the common value (5) is higher or equal than x

and, the variable y is higher or equal than  5

So, using the transitive property we can safely assume that, y is higher or equal, than x

x\leq y

Have a nice day!

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Vinil7 [7]

Answer:

a)

X[bar]_A= 71.8cm

X[bar]_B= 72cm

b)

M.A.D._A= 8.16cm

M.A.D._B= 5.4cm

c) The data set for Soil A is more variable.

Step-by-step explanation:

Hello!

The data in the stem-and-leaf plots show the heights in cm of Teddy Bear sunflowers grown in two different types of soil (A and B)

To read the data shown in the plots, remember that the first digit of the number is shown in the stem and the second digit is placed in the leaves.

The two data sets, in this case, are arranged in a "back to back" stem plot, which allows you to compare both distributions. In this type of graph, there is one single stem in the middle, shared by both samples, and the leaves are placed to its left and right of it corresponds to the observations of each one of them.

Since the stem is shared by both samples, there can be observations made only in one of the samples. For example in the first row, the stem value is 5, for the "Soil A" sample there is no leaf, this means that there was no plant of 50 ≤ X < 60 but for "Soil B" there was one observation of 59 cm.

X represents the variable of interest, as said before, the height of the Teddy Bear sunflowers.

a) To calculate the average or mean of a data set you have to add all observations of the sample and divide it by the number of observations:

X[bar]= ∑X/n

For soil A

Observations:

61, 61, 62, 65, 70, 71, 75, 81, 82, 90

The total of observations is n_A= 10

∑X_A= 61 + 61 + 62 + 65 + 70 + 71 + 75 + 81 + 82 + 90= 718

X[bar]_A= ∑X_A/n_A= 218/10= 71.8cm

For Soil B

Observations:

59, 63, 69, 70, 72, 73, 76, 77, 78, 83

The total of observations is n_B= 10

∑X_B= 59 + 63 + 69 + 70 + 72 + 73 + 76 + 77 + 78 + 83= 720

X[bar]_B= ∑X_B/n_B= 720/10= 72cm

b) The mean absolute deviation is the average of the absolute deviations of the sample. It is a summary of the sample's dispersion, meaning the greater its value, the greater the sample dispersion.

To calculate the mean absolute dispersion you have to:

1) Find the mean of the sample (done in the previous item)

2) Calculate the absolute difference of each observation and the sample mean |X-X[bar]|

3) Add all absolute differences

4) Divide the summation by the number of observations (sample size,n)

For Soil A

1) X[bar]_A= 71.8cm

2) Absolute differences |X_A-X[bar]_{A}|

|61-71.8|= 10.8

|61-71.8|= 10.8

|62-71.8|= 9.8

|65-71.8|= 6.8

|70-71.8|= 1.8

|71-71.8|= 0.8

|75-71.8|= 3.2

|81-71.8|= 9.2

|82-71.8|= 10.2

|90-71.8|= 18.2

3) Summation of all absolute differences

∑|X_A-X[bar]_A|= 10.8 + 10.8 + 9.8 + 6.8 + 1.8 + 0.8 + 3.2 + 9.2 + 10.2 + 18.2= 81.6

4) M.A.D._A=∑|X_A-X[bar]_A|/n_A= 81.6/10= 8.16cm

For Soil B

1) X[bar]_B= 72cm

2) Absolute differences |X_B-X[bar]_B|

|59-72|= 13

|63-72|= 9

|69-72|= 3

|70-72|= 2

|72-72|= 0

|73-72|= 1

|76-72|= 4

|77-72|= 5

|78-72|= 6

|83-72|= 11

3) Summation of all absolute differences

∑ |X_B-X[bar]_B|= 13 + 9 + 3 + 2 + 0 + 1 + 4 + 5 + 6 + 11= 54

4) M.A.D._B=∑ |X_B-X[bar]_B|/n_B= 54/10= 5.4cm

c)

If you compare both calculated mean absolute deviations, you can see M.A.D._A > M.A.D._B. As said before, the M.A.D. summary of the sample's dispersion. The greater value obtained for "Soil A" indicates this sample has greater variability.

I hope this helps!

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Simplify the expression by combining like terms if possible. If not possible select already simplified. 4a^2+2a+4a^2-5
vichka [17]
So the expression is: 4 a^{2} + 2a + 4 a^{2} - 5

You can combine like terms, which are terms that contain the same variables raised to the same power. That means you can combine the two 4 a^{2}. 4 a^{2} + 4 a^{2} = 8 a^{2} The other terms can't be combined.

Your final answer should be 8 a^{2} +2a-5.
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3 years ago
business plans are aimed MAINLY at A.Government Regulators B.employees C.marketing firms D.potential investors
Talja [164]
Salutations!

Business plans are mainly aimed at ----

Business plans are mainly aimed at potential investors. You need plan your business so thoroughly to gain the attention of potential investors. Potential investors are people who give you cash (capital) to help invest you in other companies or business.

Thus, your answer is option D.

Hope I helped :D
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