Question

Complete the square x^2+18x=44

Answer 1

Set the equation to 0. Subtract 44 from both sides

x^2+18x=44

x^2 + 18x (-44) = 44 (-44)

x² + 18x - 44 = 0

x 22

x -4

(x + 22)(x - 4) = 0 is your answer

hope this helps

Answer 2

Take 1/2 of linear coefient and square it
18 is linear coefient so 18/2=9, 9^2=81
add that to both sides
$x^2+18x+81=125$
factor perfect square trionomial
$(x+9)^2=125$
there, completed the square

if you want to solvesquare root both sides, don't forget positive and negative roots
$x+9=\pm \sqrt{125}$ 
$x=-9 \pm 5\sqrt{5}$

$x=-9+5\sqrt{5}$ and $x=-9-5\sqrt{5}$